繁体   English   中英

C#-从WebResponse获取响应

[英]C# - Getting response from WebResponse

我正在尝试下载放置在Internet上的RSS feed的XML源代码,但是当我的过程到达WebResponse语句(下面的第二行)时,过程停止,并且接下来什么都没有发生。 没有错误,没有例外或类似的东西。 我正在等待数十分钟,仍然没有任何反应。

WebRequest request = WebRequest.Create(source.Url);
WebResponse response = await request.GetResponseAsync(); // at this line it stops
Stream receiveStream = response.GetResponseStream();
StreamReader readStream = new StreamReader(receiveStream);

string xml = readStream.ReadToEnd().Trim();

readStream.Dispose();
response.Dispose();

知道是什么原因造成的吗?

编辑:

public static async Task<string> GetContent(string uri)
{
    WebRequest request = WebRequest.Create(url);

    using (WebResponse response = await request.GetResponseAsync().ConfigureAwait(false))
    {
        Stream receiveStream = response.GetResponseStream();
        StreamReader readStream = new StreamReader(receiveStream);

        return readStream.ReadToEnd().Trim();
    }
}

public async Task<ObservableCollection<Source>> GetArticlesFromSource()
{
    sourceDefinitions = await GetSourceDefinitions();

    string imageFolderName = "ArticleImages";
    string imageFolderPath = localFolder.Path + "\\" + imageFolderName;
    StorageFolder imageFolder = await localFolder.CreateFolderAsync(imageFolderName, CreationCollisionOption.ReplaceExisting);

    foreach (var source in sourceDefinitions)
    {
        if (source.Selected == "true")
        {
            ObservableCollection<Article> articlesStep1 = new ObservableCollection<Article>();
            /*WebRequest request = WebRequest.Create(source.Url);
            WebResponse response = await request.GetResponseAsync();
            Stream receiveStream = response.GetResponseStream();
            StreamReader readStream = new StreamReader(receiveStream);*/

            string xml = await GetContent("http://www.honzachalupa.cz/").ConfigureAwait(false);

            Debug.WriteLine(xml);
            ...

几乎可以肯定,您的应用程序将在返回的任务中进一步调用调用堆栈上的WaitResult ,这将导致死锁 ,我将在博客中详细解释。

要解决此问题,请找到上游的Wait / Result调用,并将其更改为await 换句话说,使用“一路异步”。

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM