从json对象字符串自定义反序列化

Question

我正在尝试将此JSON反序列化为一个对象，但无法达到解决方案。

Json格式：

{"option1":
  {"field1":"true","field2":"false"},
 "option2":
  {"field1":"true","field2":"false"}}

我有以下对象：

[Serializable]
public class genericFieldOptions
{
    public string option { get; set; }
    public string field { get; set; }
    public bool value{ get; set; }
}

然后是“解串器”：

public class genericFieldsConverter : JavaScriptConverter
{
    public override IEnumerable<Type> SupportedTypes
    {
        get
        {
            return new[] { typeof(genericFieldOptions) };
        }
    }

    public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
    {
        List<genericFieldOptions> p = new List<genericFieldOptions>();

        foreach (var entry in dictionary.Keys)
        {             
            try
            {
                Dictionary<string, Boolean> test = (Dictionary<string, Boolean>)dictionary[entry];//error
                p.Add(new genericFieldOptions { key = entry,   field1=test["field1"],field2=test["field2"]  });
            }
            catch { }
        }
        return p;
    }

电话：

JavaScriptSerializer serializer = new JavaScriptSerializer();
serializer.RegisterConverters(new JavaScriptConverter[] { new genericFieldsConverter() });
var example= serializer.Deserialize<List<genericFieldOptions>>(json);

如何以Dictionary<string, Dictionary<string,boolean>>的IDictionary<string, object>访问IDictionary<string, object> ？ 还是只是不可能？

我究竟做错了什么？ 还有另一种简单的方法吗？

Answer 1

简单的方法是正确制作代表序列化值的对象。 因此对于：

{"option1":
  {"field1":"true","field2":"false"},
 "option2":
  {"field1":"true","field2":"false"}}

我会做：

public class Options
{
  public Option Option1 { get; set; }
  public Option Option2 { get; set; }
}

public class Option
{
  public bool Field1 { get; set; }
  public bool Field2 { get; set; }
}

对于初学者，一种更简单的方法是使用http://json2csharp.com/ 。

Answer 2

如前所述，您可以使用Json.NET 。 如果您不想创建反序列化的类，则可以尝试使用字典，也可以使用dynamic 。

const string json = "{\"option1\":{\"field1\":true,\"field2\":false}," +
                    "\"option2\":{\"field1\":true,\"field2\":false}}";

var result1 = JsonConvert.DeserializeObject<Dictionary<string, Dictionary<string, bool>>>(json);
Console.WriteLine(result1["option2"]["field1"]);

dynamic result2 = JsonConvert.DeserializeObject(json);
Console.WriteLine(result2.option2.field1);

Answer 3

鉴于您已选择使用javascriptserializer ，首先，您需要在List<genericFieldOptions>而不是genericFieldOptions级别进行转换，因为序列化程序无法自动将JSON对象转换为List<T> 。

其次，不是将嵌套的字典强制转换为Dictionary<string, Boolean> ，而是需要强制转换为IDictionary<string, object> ，然后使用JavaScriptSerializer.ConvertToType<bool> 将每个值反序列化为 bool JavaScriptSerializer.ConvertToType<bool> 。 从而：

public class genericFieldsListConverter : JavaScriptConverter
{
    public override IEnumerable<Type> SupportedTypes
    {
        get
        {
            return new[] { typeof(List<genericFieldOptions>) };
        }
    }

    public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
    {
        var query = from entry in dictionary
                   let subDictionary = entry.Value.AsJsonObject()
                   where subDictionary != null
                   from subEntry in subDictionary
                   select new genericFieldOptions { option = entry.Key, field = subEntry.Key, value = serializer.ConvertToType<bool>(subEntry.Value) };
        return query.ToList();
    }

    public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
    {
        var list = (IList<genericFieldOptions>)obj;
        if (list == null)
            return null;
        return list
            .GroupBy(o => o.option)
            .ToDictionary(g => g.Key, g => (object)g.ToDictionary(o => o.field, o => serializer.Serialize(o.value)));
    }
}

public static class JavaScriptSerializerObjectExtensions
{
    public static bool IsJsonObject(this object obj)
    {
        return obj is IDictionary<string, object>;
    }

    public static IDictionary<string, object> AsJsonObject(this object obj)
    {
        return obj as IDictionary<string, object>;
    }
}