[英]Combine and use arithmetic on SQL values from two different tables
我有一张桌子,上面有活动客人的数据。 我可以通过此查询检索已出席的人数( membersAttended
):
SELECT COUNT(DISTINCT g.`name1`) AS `membersAttended` FROM `tmc_doorapp_guests` g LEFT JOIN `tmc_doorapp_events` e ON e.`id` = g.`event_id` WHERE `name1` REGEXP '^[0-9]+$' AND e.`date` > DATE_SUB(NOW(), INTERVAL 30 DAY) AND g.`checkin` = 1;
要检索成员总数( totalMembers
),请使用:
SELECT COUNT(DISTINCT `id`) AS `totalMembers` FROM `tmc_users`;
为了获得已参加所有成员的成员的百分比值 ( totalPercent
),我使用PHP进行了两个查询,然后进行如下计算:
$totalPercent = number_format(($membersAttended/$totalMembers*100),2);
我尝试以下面类似的方式结合两个查询和百分比计算,但是没有运气:
SELECT COUNT(DISTINCT g.`name1`) AS `membersAttended`,
COUNT(DISTINCT m.`id`) AS `totalMembers`,
(`membersAttended` * 100 / `totalMembers`) AS `totalPercent`
FROM `tmc_doorapp_guests` g, `tmc_users` m
LEFT JOIN `tmc_doorapp_events` e
ON e.`id` = g.`event_id`
WHERE `name1` REGEXP '^[0-9]+$'
AND e.`date` > DATE_SUB(NOW(), INTERVAL 30 DAY)
AND g.`checkin` = 1;
我还尝试扩展列:
SELECT COUNT(DISTINCT g.`name1`) AS `membersAttended`,
COUNT(DISTINCT m.`id`) AS `totalMembers`,
(COUNT(DISTINCT g.`name1`) * 100 / COUNT(DISTINCT m.`id`)) AS `totalPercent`
FROM `tmc_doorapp_guests` g, `tmc_users` m
LEFT JOIN `tmc_doorapp_events` e
ON e.`id` = g.`event_id`
WHERE `name1` REGEXP '^[0-9]+$'
AND e.`date` > DATE_SUB(NOW(), INTERVAL 30 DAY)
AND g.`checkin` = 1;
这给了我错误:
错误代码:1054。“ on子句”中的未知列“ g.event_id”
如何将这些SQL / PHP查询/计算组合到一个SQL查询中?
您可以使用子查询:
SELECT COUNT(DISTINCT g.`name1`) AS `membersAttended`,
(SELECT COUNT(DISTINCT `id`) FROM `tmc_users`) AS `totalMembers`,
COUNT(DISTINCT g.`name1`) * 100 / (SELECT COUNT(DISTINCT `id`)
FROM `tmc_users`) AS `totalPercent`
FROM `tmc_doorapp_guests` g
LEFT JOIN `tmc_doorapp_events` e
ON e.`id` = g.`event_id`
WHERE `name1` REGEXP '^[0-9]+$'
AND e.`date` > DATE_SUB(NOW(), INTERVAL 30 DAY)
AND g.`checkin` = 1;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.