onClick事件不适用于Android

Question

我有一个错误，很常见，因为我看到了几种解决方案，在互联网上都一样。 我试图在我的android代码上执行此操作，但是它不起作用。

我有一个按钮。 该按钮取决于微调框上的文本，应该使我转到页面或其他页面。

这是按钮的xml代码：

<Button
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:text="@string/lancer"
    android:id="@+id/startButton"
    android:layout_alignParentRight="true"
    android:layout_alignParentBottom="true"
    android:clickable="true"
    android:onClick="jumpTo"/>

及其java类：

public class Admin extends AppCompatActivity implements View.OnClickListener {

Spinner spinner_event;
Spinner spinner_activity;
Spinner spinner_wallpaper;
ArrayAdapter<CharSequence> adapter_wallpaper;
ArrayAdapter<CharSequence> adapter_event;
ArrayAdapter<CharSequence> adapter_activity;
Button startButton;
String textActivity;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.content_admin);


    spinner_event = (Spinner)findViewById(R.id.spinner_event);
    adapter_event = ArrayAdapter.createFromResource(this, R.array.events,android.R.layout.simple_spinner_dropdown_item);
    spinner_event.setAdapter(adapter_event);


    spinner_activity = (Spinner)findViewById(R.id.spinner_activity);
    adapter_activity = ArrayAdapter.createFromResource(this, R.array.activity,android.R.layout.simple_spinner_dropdown_item);
    spinner_activity.setAdapter(adapter_activity);


    spinner_wallpaper = (Spinner)findViewById(R.id.spinner_wallpaper);
    adapter_wallpaper = ArrayAdapter.createFromResource(this, R.array.wallpapers,android.R.layout.simple_spinner_dropdown_item);
    spinner_wallpaper.setAdapter(adapter_wallpaper);

    startButton = (Button)findViewById(R.id.startButton);
    startButton.setOnClickListener(this);
    }

@Override
public void onClick(View v) {
    textActivity = spinner_activity.getSelectedItem().toString();
    switch(v.getId()){

        case R.id.startButton:
        {
            if(textActivity == "Entree"){
                Intent i = new Intent(this, BadgeEntree.class);
                startActivity(i);
            }
            break;
        }
    }
}
}

我应该去我的BadgeEntree。 两者都在AndroidManifest.xml上定义，我很迷路，似乎一切正常，但不是，我在做什么错？

谢谢您的帮助

Answer 1

去掉

     startButton.setOnClickListener(this);
    }

@Override
public void onClick(View v) {
    textActivity = spinner_activity.getSelectedItem().toString();
    switch(v.getId()){

        case R.id.startButton:
        {
            if(textActivity == "Entree"){
                Intent i = new Intent(this, BadgeEntree.class);
                startActivity(i);
            }
            break;
        }
    }

做

首先，您应该调用if(textActivity.equals("Entree")而不是==

费耶

现在，当您单击按钮时，Android系统将调用活动的jumpTo（View）方法。 为了使它起作用，该方法必须是公共的并且接受View作为其唯一参数。

public void jumpTo(View i)
{
textActivity = spinner_activity.getSelectedItem().toString();
if(textActivity.equals("Entree"){
                Intent i = new Intent(this, BadgeEntree.class);
                startActivity(i);
            }
            else
            {
            Log.d("Else","Wrong");
            }
}

最后

public class Admin extends AppCompatActivity  {

Spinner spinner_event;
Spinner spinner_activity;
Spinner spinner_wallpaper;
ArrayAdapter<CharSequence> adapter_wallpaper;
ArrayAdapter<CharSequence> adapter_event;
ArrayAdapter<CharSequence> adapter_activity;
Button startButton;
String textActivity;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.content_admin);


    spinner_event = (Spinner)findViewById(R.id.spinner_event);
    adapter_event = ArrayAdapter.createFromResource(this, R.array.events,android.R.layout.simple_spinner_dropdown_item);
    spinner_event.setAdapter(adapter_event);


    spinner_activity = (Spinner)findViewById(R.id.spinner_activity);
    adapter_activity = ArrayAdapter.createFromResource(this, R.array.activity,android.R.layout.simple_spinner_dropdown_item);
    spinner_activity.setAdapter(adapter_activity);


    spinner_wallpaper = (Spinner)findViewById(R.id.spinner_wallpaper);
    adapter_wallpaper = ArrayAdapter.createFromResource(this, R.array.wallpapers,android.R.layout.simple_spinner_dropdown_item);
    spinner_wallpaper.setAdapter(adapter_wallpaper);

    startButton = (Button)findViewById(R.id.startButton);

    }


public void jumpTo(View i)
{
textActivity = spinner_activity.getSelectedItem().toString();
if(textActivity.equals("Entree"){
                Intent i = new Intent(this, BadgeEntree.class);
                startActivity(i);
            }
            else
            {
            Log.d("Else","Wrong");
            }
}


}

Answer 2

从按钮xml代码中删除onClick标记

Answer 3

在xml中删除android：onClick =“ jumpTo”

<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/lancer"
android:id="@+id/startButton"
android:layout_alignParentRight="true"
android:layout_alignParentBottom="true"
android:clickable="true"
/>

Answer 4

您必须删除此行

  <Button
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:text="@string/lancer"
    android:id="@+id/startButton"
    android:layout_alignParentRight="true"
    android:layout_alignParentBottom="true"
    android:clickable="true"
    android:onClick="jumpTo" <-----

/>

并在您的类中移动jumpTo方法的逻辑，因为现在您的类和xml中都有onCLick侦听器。 也改变这行

if(textActivity == "Entree")  

有了这个..

if(textActivity.equals("Entree"))

Answer 5

if(textActivity == "Entree")  

将上面的代码更改为

if(textActivity.equalsIgnoreCase("Entree"))

还从ur xml中删除以下代码

android:onClick="jumpTo" 

注意：如果您想对字符串进行大小写不敏感的比较，则可以使用“ equalsIgnoreCase”；如果要对字符串进行大小写敏感的比较，则可以使用“ equals”。