[英]Android getting EditText content from other Thread
在我的问题中,我有MainActivity
,一个TextView
和EditText
以及一个方法,该方法应该向TextView
发送消息并接收EditText
的内容。 问题是从EditText接收文本,并使此方法等待用户输入
我将尝试发布裁剪后的代码,以便您将获得一些有关我要实现的知识。
public class MainActivity extends Activity {
public class MonitorObject{
}
final MonitorObject mSync = new MonitorObject();
private TextView mConsoleOut;
private EditText mInputLine;
public String inputString;
public synchronized String getInputString(String value){this.inputString = value; return inputString;}
IOHandler IOhandler;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
mConsoleOut = (TextView) findViewById(R.id.consoleOut);
mInputLine = (EditText) findViewById(R.id.actionInField);
EditText editText = (EditText) findViewById(R.id.actionInField);
editText.setOnEditorActionListener(new TextView.OnEditorActionListener() {
@Override
public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
synchronized (mSync){
mSync.notify();
}
return true;
}
});
GameCycle gameCycle = new GameCycle();
Thread gameloop = new Thread(gameCycle);
gameloop.start();
}
public class GameCycle implements Runnable{
public void run(){
game();
}
}
public void game(){
findViewById(R.id.actionInField);
Integer time=0;
PlayerClass p1 = new PlayerClass(1,4);
TileClass tile = new TileClass.Forest();
Integer gamestate=0;
while(gamestate==0){
time++;
tile.initialize_tilesettings(time, p1);
tile.passed=true;
List actionResponse=new ArrayList(Arrays.asList("repeat", "type", "returnval"));
while(gamestate==0 && !actionResponse.get(1).equals("tileChange")){
actionResponse=Arrays.asList("repeat", "type", "returnval");
Boolean tileActions = true;
while(!actionResponse.get(0).equals("continue")){
//actions to be repeated
String exe=null;
tileActions=true;
List<String> params = new ArrayList<>();
<<<<<print>>>>>("\nWhat will you do?");
synchronized (mSync){
try {
mSync.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
<<<<<getinput>>>>>String inp=returnInputString();
String[] splitIn=inp.split(" ");
for(String text:splitIn){
params.add(text.toLowerCase());
}
for(ActionClass action:p1.getActions()){
if(action.method.contains(params.get(0))){
exe=action.method;
}
}
if(exe==null){
<<<<<print>>>>>("Not a valid action");
actionResponse=Arrays.asList("repeat","","");
}
else{
try{
actionResponse=p1.excecFunctionByTag(exe, Arrays.asList(p1, tile, params));
if(actionResponse==null){
throw new RuntimeException();
}
}
catch (Exception e){
for(ActionClass action:p1.getActions()){
if(exe.equals(action.method)){
String actionEnt=action.actionEntry;
<<<<<print>>>>>("\nInvalid parameters, try: "+actionEnt);
actionResponse=Arrays.asList("repeat","","");
}
}
}
return;
}
}
}
if(gamestate==1){
<<<<<print>>>>>('You died! Game over!\n\n<-<-< New Game >->->\n\n')
game();
}
else if(gamestate==2){
<<<<<print>>>>>("You have defeated the boss! Behind the fallen enemy you can see a path. You follow it and find a small village. You are safe!\n\n<-<-< New Game >->->\n\n")
game();
}
}
}
我已经用<<<<< >>>>>
标记了所需的输入/输出方法。
怜悯我的Java技能,因为这是我的第一个大型Java项目,整个结构都是从python转换而来的。
再次感谢所有帮助。
问题很简单,通常线程不会通知用户界面或主线程。 为了解决这个问题,android有AsyncTask。 您可以将AsyncTask用作:
注意:AsyncTask是一个联系到主ui线程的线程,为此它具有此onPostExecute()方法。
为了更好地了解AsyncTask,请检查以下链接: http ://www.androidhive.info/2012/01/android-json-parsing-tutorial/
好的,据我所知,您想从UI中获取一些文本(由UIThread处理),在工作线程上对其进行处理,然后将生成的文本再次发布到UI(UIThread)中的TextView
中。
这就是我在MainActivity中要做的事情:
final String line = editText.getText().toString();
// This Handler is associated with our UI thread as it is initialized here and will handle communication with Worker thread.
uiHandler = new Handler();
worker = new Worker();
worker.start();
worker.doWork(new Runnable() {
@Override
public void run() {
// processing 'line' here and posting back
// result to your textView.
// UI thread's handler is used to communicate our results back.
uiHandler.post(new Runnable() {
@Override
public void run() {
textView.setText(result);
}
});
}
});
最后是Worker线程类:
/* A worker thread for offloading heavy work so as to keep UI thread responsive
* and smooth */
public class Worker extends HandlerThread {
public final String NAME = "Worker";
private Handler handler;
public Worker() {
super("Worker", HandlerThread.NORM_PRIORITY);
}
public void prepareHandler() {
handler = new Handler(getLooper());
}
// do some work in background
public void doWork(Runnable someWork) {
prepareHandler();
handler.post(someWork);
}
}
我希望这可以帮助别人。 编码愉快!
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