如何从数组中的search（）方法返回单个print语句？

Question

我的搜索方法有问题。 我想要做的是让我的搜索方法只打印一次语句。 因此，如果我的数组不止一次包含“3”，我只想打印“3被发现”。 一次而不是检查每个值并报告阵列中该点处存在或不存在“3”。 我该怎么办？

澄清一下，这就是我所拥有的：

`0,0,0,0,0,0,0,0,0,0
4,9,6,9,0,8,5,2,8,3
Average Value: 5.4
    Maximum Value: 9
    Minimum Value: 0
    3 was not found.
    3 was not found.
    3 was not found.
    3 was not found.
    3 was not found.
    3 was not found.
    3 was not found.
    3 was not found.
    3 was not found.
    3 was found.
    2 was not found.
    2 was not found.
    2 was not found.
    2 was not found.
    2 was not found.
    2 was not found.
    2 was not found.
    2 was found.
    2 was not found.
    2 was not found.`

这就是我想要的：

0,0,0,0,0,0,0,0,0,0

4,9,6,9,0,8,5,2,8,3

Average Value: 5.4
Maximum Value: 9
Minimum Value: 0
3 was found.
2 was not found.

所以这是我的全班。 我创建了一个名为initialize的方法，它将为我的数组中的每个元素分配一个0到10之间的随机整数; 一个叫print的方法来打印出我的数组的内容; 一个名为printStats的方法，用于查找并打印数组中的平均值，最大值和最小值; 以及一个名为search的方法，它搜索我的数组（并打印结果）以获取传递给my方法的整数参数。

一切正常。

public class ArrayLab
{
    private int[] array;
    public ArrayLab(int numElements)
    {
        array = new int[numElements];
    }
    public void initialize()
    {
       array[0] = (int) (Math.random()*11);
       array[1] = (int) (Math.random()*11);
       array[2] = (int) (Math.random()*11);
       array[3] = (int) (Math.random()*11);
       array[4] = (int) (Math.random()*11);
       array[5] = (int) (Math.random()*11);
       array[6] = (int) (Math.random()*11);
       array[7] = (int) (Math.random()*11);
       array[8] = (int) (Math.random()*11);
       array[9] = (int) (Math.random()*11);
    }
    public void print()  {
        System.out.println(array[0] + "," + array[1] + "," + array[2] + "," + array[3] + "," + array[4] + "," + array[5] + "," + array[6] + "," + array[7] + "," + array[8] + "," + array[9]);
        System.out.println();
   }

       public void printStats()
    {
        double sum = 0;
        int max = 0;
        int min = 0;
        min = array[0];

        for (int i = 0; i < array.length; i++)
        {
            sum = sum + array[i];

            if (array[i] > max)
            {
                max = array[i];
            }
            else if (array[i] < min)
            {
                min = array[i];
            }
        }

        double average = sum/array.length;
        System.out.println("Average Value: " + average);
        System.out.println("Maximum Value: " + max);
        System.out.println("Minimum Value: " + min);


    }

public void search(int numChosen)
{ 
       for(int i = 0; i < array.length; i++)
        {
            if(array[i] == numChosen)
            {
                System.out.println(numChosen + " was found.");
            }
            else
            {
                System.out.println(numChosen + " was not found.");
            }
        }
   }
}

Answer 1

好吧，一旦找到数字，就不需要继续循环遍历循环。 此外，你想要在没有找到任何东西的情况下打印“未找到”，这意味着循环完成而没有打印任何东西。 所以这就是你应该如何实现它：

public void search(int numChosen)
{
    for(int i = 0; i < array.length; i++)
    {
        if(array[i] == numChosen)
        {
            System.out.println(numChosen + " was found.");
            return;
        }
    }
    System.out.println(numChosen + " was not found.");
}

在它发现某些内容的情况下，它将打印该消息并退出该方法，并且永远不会打印第二条消息。 它只会在循环结束时打印第二条消息。

Answer 2

在第一次成功搜索后，开始使用return或break语句来打破循环。

此外，在迭代阵列时，不应每次都打印出Was Not Found ”。 当阵列完全耗尽并且找不到搜索查询时，最后应该只打印一次。

以下是修改后的代码段：

boolean flag = false;
for(int i = 0; i < array.length; i++)
{
    if(array[i] == numChosen)
    {
        System.out.println(numChosen + " was found.");
        flag = true;
        break;
    }
}

if(!flag) {
    System.out.println(numChosen + " was not found.");
}

或者，您也可以执行以下操作：

for(int i = 0; i < array.length; i++)
{
    if(array[i] == numChosen)
    {
        System.out.println(numChosen + " was found.");
        return;
    }
}
System.out.println(numChosen + " was not found.");

Answer 3

您正在public void search(int numChosen)函数中显示结果。 在你的情况下，不是每次遇到匹配时打印，而是放一个计数器，然后打印一次：那个计数器与你的其余部分一起判刑。

尝试这个：

public void search(int numChosen)
{
    int count = 0;
    for (int i = 0; i < array.length; i++)
        if (array[i] == numChosen)
            count++;

    if (count == 0)
        System.out.println(numChosen + " was not found.");
    else
        System.out.println(numChosen + " was found " + count + " times.");
}