Swift 上传图片到服务器

Question

我想通过 Swift 中的 JSON 编码将图像上传到我的 Web 服务器，并尝试了其他线程和评论的一些建议。 我认为最好的解决方案如下，但我知道我收到其他错误消息这是我的代码，包括图像选择器：

    @IBAction func goToLibrary(sender: AnyObject) {

        imagePicker.allowsEditing = false
        imagePicker.sourceType = .PhotoLibrary

        presentViewController(imagePicker, animated: true, completion: nil)

    }

    func imagePickerController(picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : AnyObject]) {

        if let pickedImage = info[UIImagePickerControllerOriginalImage] as? UIImage {
            myImageView.contentMode = .ScaleAspectFit
            myImageView.image = pickedImage
        }

        dismissViewControllerAnimated(true, completion: nil)
    }

    func imagePickerControllerDidCancel(picker: UIImagePickerController) {
        dismissViewControllerAnimated(true, completion: nil)
    }

    @IBAction func uploadImage(sender: AnyObject) {

        uploadWithAlamofire();


      }


       func urlRequestWithComponents(urlString:String, parameters:Dictionary<String, String>, imageData:NSData) -> (URLRequestConvertible, NSData) {

            // create url request to send


var mutableURLRequest = NSMutableURLRequest(URL: NSURL(string: urlString)!)
        mutableURLRequest.HTTPMethod = Alamofire.Method.POST.rawValue
        let boundaryConstant = "myRandomBoundary12345";
        let contentType = "multipart/form-data;boundary="+boundaryConstant
        mutableURLRequest.setValue(contentType, forHTTPHeaderField: "Content-Type")



        // create upload data to send
        let uploadData = NSMutableData()

        // add image
        uploadData.appendData("\r\n--\(boundaryConstant)\r\n".dataUsingEncoding(NSUTF8StringEncoding)!)
        uploadData.appendData("Content-Disposition: form-data; name=\"file\"; filename=\"file.jpg\"\r\n".dataUsingEncoding(NSUTF8StringEncoding)!)
        uploadData.appendData("Content-Type: image/jpg\r\n\r\n".dataUsingEncoding(NSUTF8StringEncoding)!)
        uploadData.appendData(imageData)

        // add parameters
        for (key, value) in parameters {
            uploadData.appendData("\r\n--\(boundaryConstant)\r\n".dataUsingEncoding(NSUTF8StringEncoding)!)
            uploadData.appendData("Content-Disposition: form-data; name=\"\(key)\"\r\n\r\n\(value)".dataUsingEncoding(NSUTF8StringEncoding)!)
        }
        uploadData.appendData("\r\n--\(boundaryConstant)--\r\n".dataUsingEncoding(NSUTF8StringEncoding)!)



        // return URLRequestConvertible and NSData
        return (Alamofire.ParameterEncoding.URL.encode(mutableURLRequest, parameters: nil).0, uploadData)
    }


    // import Alamofire
    func uploadWithAlamofire() {

        // init paramters Dictionary
        var parameters = [
            "task": "task",
            "variable1": "var"
        ]

        // add addtionial parameters
        parameters["userId"] = "27"
        parameters["body"] = "This is the body text."

        // example image data
        let image = myImageView.image;
        let imageData = UIImagePNGRepresentation(image!)



        // CREATE AND SEND REQUEST ----------

        let urlRequest = urlRequestWithComponents("http://myWebserverdomain.com/project/uploadPhoto.php", parameters: parameters, imageData: imageData!)

        Alamofire.upload(urlRequest.0, data: urlRequest.1)
            .progress { (bytesWritten, totalBytesWritten, totalBytesExpectedToWrite) in
                println("\(totalBytesWritten) / \(totalBytesExpectedToWrite)")
            }
            .responseJSON { (request, response, JSON, error) in
                println("REQUEST \(request)")
                println("RESPONSE \(response)")
                println("JSON \(JSON)")
                println("ERROR \(error)")
            }    
    }

这里是 PHP 文件：

   <?php
// get picture variables
$file       = $_FILES['file']['tmp_name'];
$fileName   = $_FILES['file']['name'];
$fileType   = $_FILES['file']['type'];

// check extension
$allowedExts = array("jpg", "jpeg", "png");
$rootName = reset(explode(".", $fileName));
$extension = end(explode(".", $fileName));

// create new file name
$time = time();
$newName = $rootName.$time.'.'.$extension;

// temporarily save file
$moved = move_uploaded_file($_FILES["file"]["tmp_name"], "img/".$newName );
if ($moved) $path = "img/".$newName;

$body = $_POST['body'];
$userId = $_POST['userId'];


$time = time();
if ($moved) {
    $fullUrl = "http://myWebserverDomain.com/project/".$path;
    $arrayToSend = array('status'=>'success','time'=>$time,'body'=>$body,'userId'=>$userId, "imageURL"=>$fullUrl);
} else {
    $arrayToSend = array('status'=>'FAILED','time'=>$time,'body'=>$body,'userId'=>$userId);
}

header('Content-Type:application/json');
echo json_encode($arrayToSend);
?>

编辑：

我从这里尝试了来自“antiblank”的答案：“ 使用 Alamofire 上传带有参数的文件”与 Alamofire。

但知道我收到一个错误，内容如下：

错误信息

我希望有人知道这个问题的答案，因为我在过去 5 个小时内搜索了解决方案。

谢谢你们！

Answer 1

我已经解决了它，所以大家从这个（ 使用 Alamofire 上传带参数的文件）线程，我希望这对你有帮助。

只需删除：

 .responseJSON { (request, response, JSON, error) in
            println("REQUEST \(request)")
            println("RESPONSE \(response)")
            println("JSON \(JSON)")
            println("ERROR \(error)")

您不会从服务器获得响应，但代码本身可以工作。 我不知道为什么，但 Swift 2.0 除了这个没有。

我希望这有帮助。

问候！