如何在CoreData中保存多个条目？

Question

我有以下代码可以正确执行。 问题是它只保存最后一个条目（“Jack Daniels”，3）。 如何更改它以保存所有三个条目？

let employees = NSEntityDescription.insertNewObjectForEntityForName("Employees", inManagedObjectContext: managedObject)

employees.setValue("John Doe", forKey: "employeename")
employees.setValue(1, forKey: "id")
employees.setValue("Jane Doe", forKey: "employeename")
employees.setValue(2, forKey: "id")
employees.setValue("Jack Daniels", forKey: "employeename")
employees.setValue(3, forKey: "id")

do {
    try managedObject.save()
} catch {
    print("problem saving")
}

Answer 1

斯威夫特 4.1。 您不需要将保存代码放入 for 循环中。 只需插入所有输入，然后一次性保存它们。

 let appDelegate = UIApplication.shared.delegate as! AppDelegate
    let context = appDelegate.persistentContainer.viewContext
    let entity = NSEntityDescription.entity(forEntityName: "Employees", in: context)

    let employeeNames = ["John Doe", "Jane Doe", "Jack Daniels"]

    for (index, employee) in employeeNames.enumerated() {
      let newUser = NSManagedObject(entity: entity!, insertInto: context)
      newUser.setValue(employee, forKey: "employeename")
      newUser.setValue(index, forKey: "id")
    }

    do {
      try context.save()
    } catch {
      print("Failed saving")
    }

 // Alternative You can create your Entity class as below and insert entries.

    import CoreData
    class Employees: NSManagedObject {
      @NSManaged var employeename: String
      @NSManaged var id: String

      func addNameAndId(name: String = "", id: String = "") throws {
        if name.count > 0 {
          self.employeename = name
          self.id = id
        } else  {
          throw NSError(domain: "", code: 100, userInfo: nil)
        }
      }
    }

    // Now time to insert data

    let employeeNames = ["John Doe", "Jane Doe", "Jack Daniels"]
     for name in employeeNames {
        guard let emp = NSEntityDescription.insertNewObject(forEntityName: "Employees", into: context) as? Employees else {
                  print("Error: Failed to create a new Film object!")
                  return
                }
                do {
                  try emp.addNameAndId(name: name, id: "0")
                } catch {
                  print("Error: \(error)\nThe quake object will be deleted.")
                  context.delete(emp)
                }
        }

    // Save all the changes just made and reset the taskContext to free the cache.
          if context.hasChanges {
            do {
                 try context.save()
              } catch {
                  print("Error: \(error)\nCould not save Core Data context.")
               }
               context.reset() // Reset the context to clean up the cache and low the memory footprint.
           }

Answer 2

let employees = NSEntityDescription.insertNewObjectForEntityForName("Employees", inManagedObjectContext: managedObject)
let employees1 = NSEntityDescription.insertNewObjectForEntityForName("Employees", inManagedObjectContext: managedObject)
let employees2 = NSEntityDescription.insertNewObjectForEntityForName("Employees", inManagedObjectContext: managedObject)

employees.setValue("John Doe", forKey: "employeename")
employees.setValue(1, forKey: "id")
employees1.setValue("Jane Doe", forKey: "employeename")
employees1.setValue(2, forKey: "id")
employees2.setValue("Jack Daniels", forKey: "employeename")
employees2.setValue(3, forKey: "id")

do {
    try managedObject.save()
} catch {
    print("problem saving")
}

Answer 3

一种更紧凑（且可扩展）的方法是将您的名称数据加载到一个数组中，然后逐步执行。 您真的不想为任意长度的数组硬编码 variable1、variable2

    let employeeNames = ["John Doe", "Jane Doe", "Jack Daniels"]

    for (index, employee) in employeeNames.enumerate()
    {
        let employeeEntry = NSEntityDescription.insertNewObjectForEntityForName("Employees", inManagedObjectContext: managedObject)

        employeeEntry.setValue("John Doe", forKey: "employeename")
        employees.setValue(index, forKey: "id")

        do {
            try managedObject.save()
        } catch {
            print("problem saving")
        }
    }

Answer 4

这可能是基本的，但是像我这样的人可以从中受益，这就是发布我的答案的原因。 我从Gurjinder Singh发布的答案中发现，如果你想一次性保存多个元素，请插入一个唯一的 id，它也唯一地表示数据库中的每个值，否则它会添加元素，但所有元素都将被单个元素替换。 例如见下图：

  guard let appDelegegate = UIApplication.shared.delegate as? AppDelegate else{
        return
    }
    let managedContext = appDelegegate.persistentContainer.viewContext
    let entity = NSEntityDescription.entity(forEntityName: "Employees", in: managedContext)!
    let employeeNames = ["John Doe", "Jane Doe", "Jack Daniels"]
    for index in 0..<employeeNames.count{
        let newEmployee = NSManagedObject(entity: entity, insertInto: managedContext)
        newEmployee.setValue(self. employeeNames[index], forKey: "employeename")
    }

在这种情况下，数据库中将有三个条目，并且都是相同的。 因此，请在每个条目中插入一些唯一的 id，以将每个元素与其他元素区分开来。

   for index in 0..<employeeNames.count {
      let newEmployee = NSManagedObject(entity: entity!, insertInto: context)
      newEmployee.setValue(employeeNames[index], forKey: "employeename")
      newEmployee.setValue(index, forKey: "id")
    }

是的，不要忘记在实体中添加相同的属性；)