[英]Angular ng-repeat conditional wrap items in element (filter items in ng-repeat group)
当某些职业中未找到过滤用户时,我试图隐藏职业名称。
JS:
$scope.contacts = [
{name: 'John', occupation: 'occupation 1'},
{name: 'George', occupation: 'occupation 2'},
{name: 'Jeck', occupation: 'occupation 3'},
{name: 'Paula', occupation: 'occupation 1'},
{name: 'Scruath', occupation: 'occupation 3'}
];
HTML:
<input type="text" ng-model="query">
<div ng-repeat="(key, occupation) in contacts | groupBy: 'occupation'">
<p ng-bind="occupation[0].occupation"></p>
<div>
<div ng-repeat="contact in occupation | filter:search">
<p ng-bind="::contact.fullName"></p>
<p ng-bind="::contact.email"></p>
</div>
</div>
</div>
结果:
职业名称:“职业1”
职业名称:“职业2”
职业名称:“职业3”
有什么想法吗?
您的问题有两种解决方案:
ng-show
。 ng-repeat
上的排序。 jsfiddle上的实时示例。
angular.module('ExampleApp', ['angular.filter']) .controller('ExampleController', function($scope) { $scope.contacts = [{ name: 'John', occupation: 'occupation 1' }, { name: 'George', occupation: 'occupation 2' }, { name: 'Jeck', occupation: 'occupation 3' }, { name: 'Paula', occupation: 'occupation 1' }, { name: 'Scruath', occupation: 'occupation 3' }]; });
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.8/angular.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/angular-filter/0.5.8/angular-filter.js"></script> <div ng-app="ExampleApp"> <div ng-controller="ExampleController"> <input type="text" ng-model="query"> <h3> Filter with new array filtered </h3> <div ng-repeat="(key,occupation) in contacts| groupBy: 'occupation'" ng-show="filterOccupation.length"> <p ng-bind="key"></p> <div> <div ng-repeat="contact in filterOccupation = (occupation|filter:query)"> <p ng-bind="::contact.name"></p> </div> </div> </div> <h3> Filter with extra filtered </h3> <div ng-repeat="(key,occupation) in contacts|filter:query | groupBy: 'occupation'"> <p ng-bind="key"></p> <div> <div ng-repeat="contact in occupation|filter:query "> <p ng-bind="::contact.name"></p> </div> </div> </div> </div> </div>
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.