如何使用 linq 扩展方法执行左外连接

Question

假设我有一个左外连接：

from f in Foo
join b in Bar on f.Foo_Id equals b.Foo_Id into g
from result in g.DefaultIfEmpty()
select new { Foo = f, Bar = result }

我将如何使用扩展方法来表达相同的任务？ 例如

Foo.GroupJoin(Bar, f => f.Foo_Id, b => b.Foo_Id, (f,b) => ???)
    .Select(???)

Answer 1

对于表Bar与表Foo在 lambda 表示法中的Foo.Foo_Id = Bar.Foo_Id的（左外部）连接：

var qry = Foo.GroupJoin(
          Bar, 
          foo => foo.Foo_Id,
          bar => bar.Foo_Id,
          (x,y) => new { Foo = x, Bars = y })
       .SelectMany(
           x => x.Bars.DefaultIfEmpty(),
           (x,y) => new { Foo=x.Foo, Bar=y});

Answer 2

由于这似乎是使用方法（扩展）语法的左外连接的事实上的 SO 问题，我想我会为当前选择的答案添加一个替代方案（至少在我的经验中）更常见的是我后

// Option 1: Expecting either 0 or 1 matches from the "Right"
// table (Bars in this case):
var qry = Foos.GroupJoin(
          Bars,
          foo => foo.Foo_Id,
          bar => bar.Foo_Id,
          (f,bs) => new { Foo = f, Bar = bs.SingleOrDefault() });

// Option 2: Expecting either 0 or more matches from the "Right" table
// (courtesy of currently selected answer):
var qry = Foos.GroupJoin(
                  Bars, 
                  foo => foo.Foo_Id,
                  bar => bar.Foo_Id,
                  (f,bs) => new { Foo = f, Bars = bs })
              .SelectMany(
                  fooBars => fooBars.Bars.DefaultIfEmpty(),
                  (x,y) => new { Foo = x.Foo, Bar = y });

使用简单的数据集显示差异（假设我们正在加入值本身）：

List<int> tableA = new List<int> { 1, 2, 3 };
List<int?> tableB = new List<int?> { 3, 4, 5 };

// Result using both Option 1 and 2. Option 1 would be a better choice
// if we didn't expect multiple matches in tableB.
{ A = 1, B = null }
{ A = 2, B = null }
{ A = 3, B = 3    }

List<int> tableA = new List<int> { 1, 2, 3 };
List<int?> tableB = new List<int?> { 3, 3, 4 };

// Result using Option 1 would be that an exception gets thrown on
// SingleOrDefault(), but if we use FirstOrDefault() instead to illustrate:
{ A = 1, B = null }
{ A = 2, B = null }
{ A = 3, B = 3    } // Misleading, we had multiple matches.
                    // Which 3 should get selected (not arbitrarily the first)?.

// Result using Option 2:
{ A = 1, B = null }
{ A = 2, B = null }
{ A = 3, B = 3    }
{ A = 3, B = 3    }    

选项 2 适用于典型的左外连接定义，但正如我前面提到的，根据数据集的不同，它通常会变得不必要地复杂。

Answer 3

Group Join 方法对于实现两个数据集的连接是不必要的。

内部联接：

var qry = Foos.SelectMany
            (
                foo => Bars.Where (bar => foo.Foo_id == bar.Foo_id),
                (foo, bar) => new
                    {
                    Foo = foo,
                    Bar = bar
                    }
            );

对于左连接，只需添加 DefaultIfEmpty()

var qry = Foos.SelectMany
            (
                foo => Bars.Where (bar => foo.Foo_id == bar.Foo_id).DefaultIfEmpty(),
                (foo, bar) => new
                    {
                    Foo = foo,
                    Bar = bar
                    }
            );

EF 和 LINQ 到 SQL 正确转换为 SQL。 对于 LINQ 到 Objects ，最好使用 GroupJoin 加入，因为它在内部使用 Lookup 。 但是，如果您正在查询数据库，那么跳过 GroupJoin 是 AFAIK 的表现。

与 GroupJoin().SelectMany() 相比，这种方式对我来说 Personlay 更具可读性

Answer 4

您可以创建扩展方法，例如：

public static IEnumerable<TResult> LeftOuterJoin<TSource, TInner, TKey, TResult>(this IEnumerable<TSource> source, IEnumerable<TInner> other, Func<TSource, TKey> func, Func<TInner, TKey> innerkey, Func<TSource, TInner, TResult> res)
    {
        return from f in source
               join b in other on func.Invoke(f) equals innerkey.Invoke(b) into g
               from result in g.DefaultIfEmpty()
               select res.Invoke(f, result);
    }

Answer 5

改进 Ocelot20 的答案，如果你有一个表，你只需要从外部加入 0 或 1 行，但它可能有多个，你需要订购你的加入表：

var qry = Foos.GroupJoin(
      Bars.OrderByDescending(b => b.Id),
      foo => foo.Foo_Id,
      bar => bar.Foo_Id,
      (f, bs) => new { Foo = f, Bar = bs.FirstOrDefault() });

否则，您在联接中获得的哪一行将是随机的（或者更具体地说，无论哪个数据库碰巧先找到）。

Answer 6

虽然接受的答案有效并且对 Linq 到 Objects 有好处，但它让我烦恼的是 SQL 查询不仅仅是一个直接的左外连接。

以下代码依赖于LinqKit 项目，它允许您传递表达式并将它们调用到您的查询中。

static IQueryable<TResult> LeftOuterJoin<TSource,TInner, TKey, TResult>(
     this IQueryable<TSource> source, 
     IQueryable<TInner> inner, 
     Expression<Func<TSource,TKey>> sourceKey, 
     Expression<Func<TInner,TKey>> innerKey, 
     Expression<Func<TSource, TInner, TResult>> result
    ) {
    return from a in source.AsExpandable()
            join b in inner on sourceKey.Invoke(a) equals innerKey.Invoke(b) into c
            from d in c.DefaultIfEmpty()
            select result.Invoke(a,d);
}

可以如下使用

Table1.LeftOuterJoin(Table2, x => x.Key1, x => x.Key2, (x,y) => new { x,y});

Answer 7

将 Marc Gravell 的答案转换为扩展方法，我做了以下操作。

internal static IEnumerable<Tuple<TLeft, TRight>> LeftJoin<TLeft, TRight, TKey>(
    this IEnumerable<TLeft> left,
    IEnumerable<TRight> right,
    Func<TLeft, TKey> selectKeyLeft,
    Func<TRight, TKey> selectKeyRight,
    TRight defaultRight = default(TRight),
    IEqualityComparer<TKey> cmp = null)
{
    return left.GroupJoin(
            right,
            selectKeyLeft,
            selectKeyRight,
            (x, y) => new Tuple<TLeft, IEnumerable<TRight>>(x, y),
            cmp ?? EqualityComparer<TKey>.Default)
        .SelectMany(
            x => x.Item2.DefaultIfEmpty(defaultRight),
            (x, y) => new Tuple<TLeft, TRight>(x.Item1, y));
}

Answer 8

有一个简单的解决方案

只需在您的 Select 中使用.HasValue

.Select(s => new 
{
    FooName = s.Foo_Id.HasValue ? s.Foo.Name : "Default Value"
}

非常简单，不需要 groupjoin 或其他任何东西

Answer 9

Marc Gravell's answer turn into an extension method that support the IQueryable<T> interface is given in this answer ，并增加了对 C# 8.0 NRT 的支持，内容如下：

#nullable enable
using LinqKit;
using LinqKit.Core;
using System.Linq.Expressions;

...

/// <summary>
/// Left join queryable. Linq to SQL compatible. IMPORTANT: any Includes must be put on the source collections before calling this method.
/// </summary>
public static IQueryable<TResult> LeftJoin<TOuter, TInner, TKey, TResult>(
    this IQueryable<TOuter> outer,
    IQueryable<TInner> inner,
    Expression<Func<TOuter, TKey>> outerKeySelector,
    Expression<Func<TInner, TKey>> innerKeySelector,
    Expression<Func<TOuter, TInner?, TResult>> resultSelector)
{
    return outer
        .AsExpandable()
        .GroupJoin(
            inner,
            outerKeySelector,
            innerKeySelector,
            (outerItem, innerItems) => new { outerItem, innerItems })
        .SelectMany(
            joinResult => joinResult.innerItems.DefaultIfEmpty(),
            (joinResult, innerItem) =>
                resultSelector.Invoke(joinResult.outerItem, innerItem));
}

Answer 10

我有这个问题的书签，需要每年左右参考。 每次我重温这个，我发现我已经忘记了它是如何工作的。 这是对正在发生的事情的更详细的解释。

GroupJoin就像GroupBy和Join的混合体。 GroupJoin基本上通过连接键对外部集合进行分组，然后将分组连接到连接键上的内部集合。 假设我们有客户和订单。 如果您在各自的 ID 上进行GroupJoin ，则结果是{Customer, IGrouping<int, Order>}的可枚举。 GroupJoin有用的原因是，即使外部集合不包含匹配的对象，也会表示所有内部对象。 对于没有订单的客户， IGrouping<int, Order>只是空的。 一旦我们有了{ Customer, IGrouping<int, Order> } ，我们就可以按原样使用，过滤掉没有订单的结果，或者用SelectMany展平以获得像传统的 LINQ Join一样的结果。

如果有人想单步调试调试器并了解它是如何工作的，这是一个完整的示例：

using System;
using System.Linq;
                    
public class Program
{
    public static void Main()
    {
        //Create some customers
        var customers = new Customer[]
        {
            new Customer(1, "Alice"),
            new Customer(2, "Bob"),
            new Customer(3, "Carol")
        };
        
        //Create some orders for Alice and Bob, but none for Carol
        var orders = new Order[]
        {
            new Order(1, 1),
            new Order(2, 1),
            new Order(3, 1),
            new Order(4, 2),
            new Order(5, 2)
        };

        //Group join customers to orders.
        //Result is IEnumerable<Customer, IGrouping<int, Order>>. 
        //Every customer will be present. 
        //If a customer has no orders, the IGrouping<> will be empty.
        var groupJoined = customers.GroupJoin(orders,
                              c => c.ID,
                              o => o.CustomerID,
                              (customer, order) => (customer, order));

        //Display results. Prints:
        //    Customer: Alice (CustomerID=1), Orders: 3
        //    Customer: Bob (CustomerID=2), Orders: 2
        //    Customer: Carol (CustomerID=3), Orders: 0
        foreach(var result in groupJoined)
        {
            Console.WriteLine($"Customer: {result.customer.Name} (CustomerID={result.customer.ID}), Orders: {result.order.Count()}");
        }
        
        //Flatten the results to look more like a LINQ join
        //Produces an enumerable of { Customer, Order }
        //All customers represented, order is null if customer has no orders
        var flattened = groupJoined.SelectMany(z => z.order.DefaultIfEmpty().Select(y => new { z.customer, y }));

        //Get only results where the outer table is null.
        //roughly equivalent to: 
        //SELECT * 
        //FROM A 
        //LEFT JOIN B 
        //ON A.ID = B.ID 
        //WHERE B.ID IS NULL;
        var noMatch = groupJoined.Where(z => z.order.DefaultIfEmpty().Count() == 0);
    }
}

class Customer
{
    public int ID { get; set; }
    public string Name { get; set; }

    public Customer(int iD, string name)
    {
        ID = iD;
        Name = name;
    }
}

class Order
{
    static Random Random { get; set; } = new Random();

    public int ID { get; set; }
    public int CustomerID { get; set; }
    public decimal Amount { get; set; }

    public Order(int iD, int customerID)
    {
        ID = iD;
        CustomerID = customerID;
        Amount = (decimal)Random.Next(1000, 10000) / 100;
    }
}