使用php在数据库中插入多个值

Question

我正在尝试在数据库中插入多个值。 但是我找不到解决方案来完成我想要的事情。

我的问题是我有一个值数组，例如("6.40","6.50","7.00","7.10","7.20","7.30") ，我想在每行中插入这些值，例如6.40 will将其存储在与ID“ 1”相对应的一行中。

同样，“ 6.50”将存储在ID“ 2”中。 该ID将只是自动递增。

同样，它将在数据库中插入值，直到数组为空。 如果有人对如何解决此问题有任何想法，请帮助我！ 请忍受我的怀疑。 我是PHP新手。 提前致谢。

 for ($i=0;$i < count($slot_timings1); $i++)
 { 
    $q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,slot_timings)');
    $q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=‌​>$slot_timings));
 } 
 $counts = $q->rowCount(); 
 return $counts; 

Answer 1

尝试这样的事情。

foreach($slot_timings1 as $data)
     { 
        $q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,slot_timings)');
        $q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=‌​>$data));
     } 

Answer 2

尝试这个：

if(is_array($slot_timings1) && !empty($slot_timings1))
{
 foreach ($slot_timings1 as $slot_timing)
 { 
$q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,:slot_timings)');

 $q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=>$slot_timing));
} 

return count($slot_timings1);    
}

Answer 3

if(is_array($slot_timings1)){


 sort($slot_timings1); //Sort the elements of the array in ascending

$sql = "INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES ";

$query_val = array();
foreach($slot_timings1 as $gettime){

    $row1 = $doctor_name;
    $row2 = $doctor_id;
    $row3 = $appointment_date;
    $row4 = $slot_name;
    $row5 = $gettime;
    $query_val[] = "('$row1', '$row2', '$row3', '$row4', '$row5')";
}

$sql .= implode(',', $query_val);

mysql_query($sql) or exit(mysql_error()); 
}

Answer 4

尝试这个：

for ($i=0;$i < count($slot_timings1); $i++)
 { 
$q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,slot_timings)');
 $q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=‌​>$slot_timings1[$i]));
} 
$counts = $q->rowCount(); 
return $counts;