[英]Selecting ONLY Duplicates from a joined tables query
我有以下查询,我试图连接两个与其 ID 匹配的表,以便我可以在“c.code”中获取重复的值。 我已经尝试了很多查询,但没有任何效果。 我的数据库中有 500k 行,通过这个查询我只得到 5k,这是不对的。 我肯定它至少是 200K。 我也尝试使用 Excel,但它无法处理。 有任何想法吗? 提前谢谢大家。
SELECT c.code, c.name as SCT_Name, t.name as SYNONYM_Name, count(c.code)
FROM database.Terms as t
join database.dbo.Concepts as c on c.ConceptId = t.ConceptId
where t.TermTypeCode = 'SYNONYM' and t.ConceptTypeCode = 'NAME_Code' and c.retired = '0'
Group by c.code, c.name, t.name
HAVING COUNT(c.code) > = 1
Order by c.code
with data as (
select c.code, c.name as SCT_Name, t.name as SYNONYM_Name
from database.Terms as t inner join database.dbo.Concepts as c
on c.ConceptId = t.ConceptId
where
t.TermTypeCode = 'SYNONYM'
and t.ConceptTypeCode = 'NAME_Code'
and c.retired = '0'
)
select *
--, (select count(*) from data as d2 where d2.code = data.code) as code_count
--, count(*) over (partition by code) as code_count
from data
where code in (select code from data group by code having count(*) > 1)
order by code
如果您只想复制 c.code,那么您的 Group By 是错误的(您的 Have 子句也是错误的)。 尝试这个:
SELECT c.code
FROM database.Terms as t
join database.dbo.Concepts as c on c.ConceptId = t.ConceptId
where t.TermTypeCode = 'SYNONYM' and t.ConceptTypeCode = 'NAME_Code' and c.retired = '0'
Group by c.code
HAVING COUNT(c.code) > 1
这将返回您拥有多个 c.code 值的所有行。
您需要使用 INTERSECT 而不是 JOIN。 基本上你在第一个表上执行选择然后与第二个表相交。 结果是重复的行。
但是,只选择 id 列,否则相交将无法按预期工作。
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