获取多行并将其存储到变量。 MySQL和PHP

Question

我正在为系统创建一个平均公里数运行计算器。 因此，我试图在数据库上获取最后两个日期和最后两个日期。

这是我当前的代码：

<?php

$conn = mysqli_connect('localhost','root','','mypms');

 $sqldates = "SELECT dateinput FROM sched ORDER BY dateinput DESC LIMIT 2";
 $sqlrun = "SELECT reading FROM sched ORDER BY reading DESC LIMIT 2"; 

 $resultdate = mysql_query($conn,$sqldates);
 $resultrun = mysql_query($conn,$sqlrun);


 while($rowdate = mysql_fetch_assoc($resultdate))
 {
     this ->
 }

 $date_difference = $date2 - $date1;

 while($rowrun = mysql_fetch_assoc($resultrun))
 {
     this ->
 }

 $run_difference = $run2 - $run1;
 $averagerun = $run_difference/$date_difference

 echo $averagerun;
?>

我应该写上我的什么this ，所以我可以存储我的$ resultrun和$ resultdate到DATE1，$ DATE2和$ RUN1，$ RUN2。

注意：dateinput的datetype是我的mysqldatabase上的日期。

Answer 1

请尝试使用此查询-它会返回您的结果

SELECT 
run_difference/date_difference AS averagerun
FROM
    (
        SELECT
        DATEDIFF(date2,date1) AS date_difference,
        reading2 - reading1 AS run_difference
        FROM
        (
            SELECT 
            (SELECT dateinput FROM sched ORDER BY dateinput LIMIT 0, 1) AS date1, 
            (SELECT dateinput FROM sched ORDER BY dateinput LIMIT 1, 1) AS date2,
            (SELECT reading FROM sched ORDER BY reading DESC LIMIT 0, 1) AS reading1,
            (SELECT reading FROM sched ORDER BY reading DESC LIMIT 1, 1) AS reading2 
            FROM DUAL
        ) t1
    )t2

或“一个班轮”：

SELECT 
    (SELECT reading FROM sched ORDER BY reading DESC LIMIT 1, 1)-(SELECT reading FROM sched ORDER BY reading DESC LIMIT 0, 1)   /   DATEDIFF((SELECT dateinput FROM sched ORDER BY dateinput LIMIT 1, 1), (SELECT dateinput FROM sched ORDER BY dateinput LIMIT 0, 1))  AS averagerun
FROM DUAL