[英]my program is to post to mysql database. I am having issues, and I have tried for hours to determine where I am wrong
[英]I have tried to update data into database in this way but something maybe not working for the first if statement where if ( !empty($_POST) )
我试图以这种方式将数据更新到数据库中,但对于第一个if语句,如果if(!empty($ _ POST)),某些操作可能无法正常工作,请参见此图以了解清楚
<?php require_once '../App/start.php'; if ( !empty($_POST) ) { $id = $_POST['id']; $label = $_POST['label']; $title = $_POST['title']; $slug = $_POST['slug']; $body = $_POST['body']; $updatePage = $db->prepare("UPDATE pages SET label=:label, title=:title,body =:body, slug=:slug, updated=NOW() WHERE id = :id"); $updatePage->execute([ 'id' => $id, 'label' => $label, 'title' => $title, 'body' => $body, 'slug' => $slug ]); header('Location:' . BASE_URL . '/index.php'); } if (!isset($_GET['id'])) { header('Location:' . BASE_URL . '/Admin/list.php'); die(); } $edit = $db->prepare("SELECT id, label, title, body, slug FROM pages WHERE id = :id"); $edit->execute(['id' => $_GET['id']]); $edits = $edit->fetch(PDO::FETCH_ASSOC); require_once VIEW_ROOT . '/Admin/edit.php';
从此代码中,第一条语句无法将数据更新到数据库
如果要检查方法和值,则应像下面那样测试帖子。
if ($_SERVER['REQUEST_METHOD'] == 'POST' && isset ($_POST ['id']))
否则, if ( isset ($_POST ['id']) )
就足够了。
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