插入时出现sqlite异常

Question

我已经尝试了很长时间，我的大脑已经累了。我试图通过微调器，无线电和edittext获取用户输入。以下是我获得所有输入的主要活动代码。

public class SQLiteActivity extends Activity implements AdapterView.OnItemSelectedListener, RadioGroup.OnCheckedChangeListener {

private String crop;
private String flowrate;
private String soil;
private String threshold;
private String limit;
SqliteHelper sqliteHelper;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_shared);
    crop = "";
    flowrate = "";
    soil = "";
    threshold="";
    limit="";
    Spinner spinnerZodiac = (Spinner) findViewById(R.id.spinnerZodiac);
    spinnerZodiac.setOnItemSelectedListener(this);
    ArrayAdapter<CharSequence> adapter = ArrayAdapter.createFromResource(this,
            R.array.soil, android.R.layout.simple_spinner_item);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    spinnerZodiac.setAdapter(adapter);

    RadioGroup radioGroupGender = (RadioGroup) findViewById(R.id.radioGroupFlowrate);
    radioGroupGender.setOnCheckedChangeListener(this);

    sqliteHelper = new SqliteHelper(this);
}

@Override
public void onCheckedChanged(RadioGroup radioGroup, int i) {
    int radioButtonId = radioGroup.getCheckedRadioButtonId();
    RadioButton radioButton = (RadioButton)radioGroup.findViewById(radioButtonId);
    flowrate = radioButton.getText().toString();
}
public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
    soil = parent.getItemAtPosition(position).toString();
}

public void onNothingSelected(AdapterView<?> parent) {
    // An interface callback
}

public void save(View view) {
    crop = ((EditText)findViewById(R.id.txtCrop)).getText().toString();
    threshold = ((EditText)findViewById(R.id.txtThreshold)).getText().toString().trim();
    limit= ((EditText)findViewById(R.id.txtLimit)).getText().toString().trim();
    if (crop.isEmpty()){
        Toast.makeText(getApplicationContext(), "Crop type cannot be empty!", Toast.LENGTH_LONG).show();
        return;
    }
    boolean result = sqliteHelper.saveUser(crop, flowrate, soil,threshold,limit);
    if (result){
        Toast.makeText(getApplicationContext(), "You have been saved!", Toast.LENGTH_LONG).show();
    } else {
        Toast.makeText(getApplicationContext(), "Failed to save!", Toast.LENGTH_LONG).show();
    }
}
public void retrieve(View view) {
    crop = ((EditText)findViewById(R.id.txtCrop)).getText().toString();
    Cursor cursor = sqliteHelper.getUser(crop);
    if (cursor.getCount() != 0) {
        cursor.moveToFirst();
        crop = cursor.getString(cursor.getColumnIndex("crop"));
        flowrate= cursor.getString(cursor.getColumnIndex("flowrate"));
        soil = cursor.getString(cursor.getColumnIndex("soil"));
        threshold=cursor.getString(cursor.getColumnIndex("threshold"));
        limit=cursor.getString(cursor.getColumnIndex("limit"));
        if (!cursor.isClosed()) {
            cursor.close();
        }  
        setUI();
    }
}
protected void setUI(){
    ((TextView)findViewById(R.id.txtCrop)).setText(crop);
    if (flowrate.equals("50")){
        ((RadioButton)findViewById(R.id.radMale)).setChecked(true);
    } else if (flowrate.equals("60")){
        ((RadioButton)findViewById(R.id.radFemale)).setChecked(true);
    }
    Resources resource = getResources();
    String[] zodiacArray = resource.getStringArray(R.array.soil);

    for(int i = 0; i < zodiacArray.length; i++){
        if(zodiacArray[i].equals(soil)){
            ((Spinner)findViewById(R.id.spinnerZodiac)).setSelection(i);
        }
    }
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
    getMenuInflater().inflate(R.menu.sqlite, menu);
    return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
    int id = item.getItemId();
    if (id == R.id.action_settings) {
        return true;
    }
    return super.onOptionsItemSelected(item);
}

下面是将输入的详细信息保存在sqlite数据库中的函数（sqlitehelper类）

public boolean saveDetail(String crop, String flowrate,String soil,String threshold,String limit)
{
    Cursor cursor = getUser(crop);
    SQLiteDatabase db = this.getWritableDatabase();
    ContentValues contentValues = new ContentValues();
    contentValues.put("flowrate", flowrate);
    contentValues.put("soil", soil);
    contentValues.put("threshold", threshold);
    contentValues.put("limit", limit);
    long result;
    if (cursor.getCount() == 0) { 
        contentValues.put("crop", crop);
        result = db.insert("configuration", null, contentValues);
    } else { 
        result = db.update("configuration", contentValues, "crop=?", new String[] { crop });
    }
    if (result == -1) {
        return false;
    } else {
        return true;
    }
}
public Cursor getDetail(String crop){
    SQLiteDatabase db = this.getReadableDatabase();
    String sql = "SELECT * FROM configuration WHERE crop=?";
    return db.rawQuery(sql, new String[] { crop } );
}

在执行时会抛出异常

 Error inserting crop=tea threshold=10 soil=Alluvial limit=20 flowrate=15
                                                                  android.database.sqlite.SQLiteException: near "limit": syntax error (code 1): , while compiling: INSERT INTO configuration(crop,threshold,soil,limit,flowrate) VALUES (?,?,?,?,?)

非常感谢您的回答。我将变量名更改为bound，但现在没有显示该错误。但是我得到了另一个错误。

Error inserting crop=un threshold=11 bound=111 soil=Alluvial flowrate=50
                                                                       android.database.sqlite.SQLiteException: table configuration has no column named threshold (code 1): , while compiling: INSERT INTO configuration(crop,threshold,bound,soil,flowrate) VALUES (?,?,?,?,?)

Answer 1

Limit是一个保留的SQL词，请尝试对其进行更改，它应该能很好地工作。 如果您不想更改它，可以使用：

`"Limit"`    

`[Limit]`

`Limit`

此处有更多信息： https : //www.sqlite.org/lang_keywords.html

Answer 2

您不能在sqlite中使用“ LIMIT”作为列名以获取更多信息，请访问http://www.sqlite.org/lang_keywords.html

Answer 3

查看查询和Exception消息，“ limit”是一个SQLite关键字，用于限制SELECT语句返回的数据量。 这就是为什么您会获得异常。 它与您的列名冲突。 例如，将列名更改为mylimit，它将起作用

第二个错误可能是您稍后在数据库中添加了列名“ crop”。 您可以通过更改database_version来解决

Answer 4

1.Limit是SQLite中的关键字，这就是为什么我收到上述错误，将变量名更改为其他名称。 2.我最初只创建了3列的表，但随后又添加了2列，在这种情况下，您可能需要做一个清除数据才能再次创建数据库。 只有创造的过程发生在第一次执行，如果数据库版本已经改变，都到下面的onUpgrade method.Read赛义德的评论也可以得到更新去这里