[英]Serialize XML array, attribute to Object
如何定义对象以反序列化以下XML:
<body>
<S1 A="1">
<S2 B="1">
<S3 C="1"/>
<S3 C="1"/>
</S2>
<S2 B="2"/>
</S1>
<S1 A="2"/>
我强烈建议使用xsd.exe ,它可以帮助从XDR,XML和XSD文件或从运行时程序集中的类生成XML模式或公共语言运行时类。
xsd.exe PathToXmlFile.xml /outputdir:OutputDir
并按Enter
-这将生成*.xsd
文件 xsd.exe PreviouslyCreatedXsdFile.xsd /classes /outputdir:OutputDir
并按Enter
-这将生成*.cs
文件(类定义)。 就这样!
尝试!
尝试这个....
正在使用.....
using System;
using System.Xml.Serialization;
using System.Collections.Generic;
using System.IO;
using System.Text;
using System.Xml;
课.....
[XmlRoot(ElementName = "S3")]
public class S3
{
[XmlAttribute(AttributeName = "C")]
public string C { get; set; }
}
[XmlRoot(ElementName = "S2")]
public class S2
{
[XmlElement(ElementName = "S3")]
public List<S3> S3 { get; set; }
[XmlAttribute(AttributeName = "B")]
public string B { get; set; }
}
[XmlRoot(ElementName = "S1")]
public class S1
{
[XmlElement(ElementName = "S2")]
public List<S2> S2 { get; set; }
[XmlAttribute(AttributeName = "A")]
public string A { get; set; }
}
[XmlRoot(ElementName = "body")]
public class Body
{
[XmlElement(ElementName = "S1")]
public List<S1> S1 { get; set; }
}
码.....
string strXML = File.ReadAllText("xml.xml");
byte[] bufXML = ASCIIEncoding.UTF8.GetBytes(strXML);
MemoryStream ms1 = new MemoryStream(bufXML);
// Deserialize to object
XmlSerializer serializer = new XmlSerializer(typeof(Body));
try
{
using (XmlReader reader = new XmlTextReader(ms1))
{
Body deserializedXML = (Body)serializer.Deserialize(reader);
}// put a break point here and mouse-over deserializedXML….
}
catch (Exception ex)
{
throw;
}
您的XML .....
<body>
<S1 A="1">
<S2 B="1">
<S3 C="1"/>
<S3 C="1"/>
</S2>
<S2 B="2"/>
</S1>
<S1 A="2"/>
</body>
我添加了结束标签.....我正在从应用程序构建文件夹xml.xml中的文件中读取XML字符串,您将需要从其他位置获取XML字符串或创建xml。 xml文件,并保存XML以使上面的代码正常工作
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