使用strpos（）时遇到问题

Question

此函数会产生6个匹配项，但应该会产生2个匹配项。 我不确定我在这里做错了什么。

public function displayPrize() {
        $testString = "The cow jumped over the moon";
        $userString = "The cow";

        $magicArray = (explode(" ", $testString));

        foreach ($magicArray as $value) {
            if (strpos(" ", $userString, $value) !== false) {
                $count++;
            }
        }

        echo $count . ' matches';
    }

Answer 1

if (strpos(" ", $userString, $value) !== false)

必须成为

if (strpos($userString, $value) !== false)

Answer 2

使用array_intersect（）的替代方法：

$testString = 'The cow jumped over the moon';
$userString = 'The cow';

$testStringArray = explode(' ', $testString);
$userStringArray = explode(' ', $userString);

$result = count( array_intersect($testStringArray, $userStringArray) ); // 2