PHP检查数组中的值是否小于每个ID的数组中的先前值

Question

我有一个存储ID的数组，每个ID都有一个包含起始值和结束值的数组。 我的目标是检查起始值是否小于数组中它前面的项的结束值。

这有效但我的循环不关心ID，我需要一种方法来执行此ID

这是我的数组的样子：

Array
(
    [892] => Array
        (
            [41] => Array
                (
                    [0] => Array
                        (
                            [start] => 0930
                            [end] => 1200
                        )

                )

        )

    [897] => Array
        (
            [41] => Array
                (
                    [0] => Array
                        (
                            [start] => 1000
                            [end] => 1230
                        )

                )

        )

    [898] => Array
        (
            [41] => Array
                (
                    [0] => Array
                        (
                            [start] => 1100
                            [end] => 1300
                        )

                )

        )

    [901] => Array
        (
            [52] => Array
                (
                    [0] => Array
                        (
                            [start] => 0930
                            [end] => 1030
                        )

                )

        )

    [903] => Array
        (
            [52] => Array
                (
                    [0] => Array
                        (
                            [start] => 0930
                            [end] => 1030
                        )

                )

        )

    [904] => Array
        (
            [41] => Array
                (
                    [0] => Array
                        (
                            [start] => 1000
                            [end] => 1230
                        )

                )

        )

)

这就是我的循环：

$foundOverlap = false;
$prevEnd = null;
foreach($slots as $s){

     $startHour = $s[0]['start'];
     $endHour = $s[0]['end'];
     echo $startHour . '<br>';
     echo $endHour . '<br>';

     if($prevEnd !== null && $startHour < $prevEnd){
         $foundOverlap = true;
         $counter++;
     } 

     if($foundOverlap){
        echo 'overlap <br>';
     }else{
        echo 'no overlap <br>';
     }

     $prevEnd = $endHour;

}

结果我得到没有重叠（好），重叠（好），重叠（好），重叠（坏！）这应该没有重叠。 但它说重叠，因为它检查前一个数组项并不关心attractieID是什么...

任何人都知道如何解决这个问题？

我会太感激了!!

提前致谢！

Answer 1

从Muhammad Kashif Abbasi的评论中我想给你一个解决方案

试试这个代码

$foundOverlap = false;
$prevEnd = null;
$preID = null;
foreach($slots as $s){

     $startHour = $s[0]['start'];
     $endHour = $s[0]['end'];
     $currentID = $s['attractieID']; //got the current attractieID
     echo $startHour . '<br>';
     echo $endHour . '<br>';

     if($prevEnd !== null && $startHour < $prevEnd && $currentID == $preID){ // checked current id and previous id
         $foundOverlap = true;
         $counter++;
     } 

     if($foundOverlap){
        echo 'overlap <br>';
     }else{
        echo 'no overlap <br>';
     }
     $foundOverlap = false; //reseted $foundOverlap
     $prevEnd = $endHour;
     $preID = $currentID; //set the current id as previous id

}

Answer 2

看一下这个

$result = [];
foreach($array as $element) {
    if(!isset($result[$element['attractiveID']])) {
        $result[$element['attractiveID']]['overlap'] = false;
        $result[$element['attractiveID']]['prevHour'] = $element[0]['end'];
        continue;
    }

    if($element[0]['start'] < $result[$element['attractiveID']]['prevHour']) {
        $result[$element['attractiveID']]['overlap'] = true;
    }

    $result[$element['attractiveID']]['prevHour'] = $element[0]['end'];
}

和数组传递：

$array = [
    [
        'attractiveID' => 41,
        [
            'start' => 930,
            'end' => 1200
        ]
    ],
    [
        'attractiveID' => 41,
        [
            'start' => 1000,
            'end' => 1230
        ]
    ],
    [
        'attractiveID' => 41,
        [
            'start' => 1100,
            'end' => 1300
        ]
    ],
    [
        'attractiveID' => 52,
        [
            'start' => 1000,
            'end' => 1230
        ]
    ],
];