当我单击删除按钮下一个图像被删除而不是我在php mysql图像库中单击的图像

Question

表格上传图片

 <form method='post' action='' enctype='multipart/form-data'>
 <input type='file' name='file'>
 <input type='submit' value='Upload'>
 </form>

php编码，用于从创建用于存储要删除图像的ID的数据库会话插入和显示图像库

<?php 
session_start();
$conn = mysqli_connect("localhost","root","","img") or die ("connection failed ");
if ($_FILES)
{
$name = $_FILES['file']['name'];
$type = $_FILES['file']['type'];
$insert = "insert into image (image) values ('".$name."')";
$sql = mysqli_query($conn,$insert);
}
$view = mysqli_query($conn,"select * from image");
while($row = mysqli_fetch_array($view))
{   
extract($row);
echo "<form action=\"\" method=\"post\"><input type=\"submit\" name=\"del\" value=\"submit\"></form><a href=\"$image\"><img src=\"$image\" /></a>";
if(isset($_POST['del']))
{   
$_SESSION['del_id'] = $id;
header("location:del.php");
}
}
?>

del.php会话ID将被删除

<?php
session_start();
$conn = mysqli_connect("localhost","root","","img") or die ("connection failed ");
$id = $_SESSION['del_id'];
$sql = mysqli_query($conn,"delete from image where id = '$id' ");
header("location:x.php");
?>

Answer 1

我看不到从哪里获取id值来设置del_id. 但是，您将需要以下内容：

更换：

 echo "<form action=\"\" method=\"post\"><input type=\"submit\" name=\"del\" value=\"submit\"></form><a href=\"$image\"><img src=\"$image\" /></a>";

有了这个：

echo "<form action=\"\" method=\"post\">";
echo "<input type=\"submit\" name=\"del\" value=\"submit\">";
echo "<input type=\"hidden\" name=\"del_id\" value=\"$row['id']\">";
echo "</form>";
echo "<a href=\"$image\"><img src=\"$image\" /></a>";

并更改$_SESSION['del_id'] = $id; 到$_SESSION['del_id'] = $_POST['del_id'];

Answer 2

$_SESSION['del_id'] = $id;

您从哪里获取此$ id？