AutoCompleteTextView文本过滤

Question

我正在尝试使用AutoCompleteTextView进行过滤，但过滤器出现问题。 它返回ArrayList中的所有项目，而不是过滤后的项目。 下面是我的代码：

 Filter nameFilter = new Filter() {
    @Override
    public String convertResultToString(Object resultValue) {
        String str = ((State)(resultValue)).getName();
        Log.e("Conv"+TAG, str);
        return str;
    }
    @Override
    protected FilterResults performFiltering(CharSequence constraint) {
        if(constraint != null) {
            suggestions.clear();
            for (State customer : itemsAll) {
                Log.e("Ite "+TAG, "" + itemsAll.size());
                Log.e("Cons " + TAG, constraint.toString());
                Log.e("Sta" + TAG, customer.getName()); //This is always null
                if(customer.getName().toLowerCase().contains(constraint.toString().toLowerCase())) {
                    suggestions.add(customer);
                }
            }
            FilterResults filterResults = new FilterResults();
            filterResults.values = suggestions;
            filterResults.count = suggestions.size();
            return filterResults;
        } else {
            return new FilterResults();
        }
    }
    @Override
    protected void publishResults(CharSequence constraint, FilterResults results) {
        List<State> filteredList = (ArrayList<State>) results.values;
        if(results != null && results.count > 0) {
            clear();
            Log.e("D "+TAG, ""+results.count);
            for (State c : filteredList) {
                Log.e("The "+TAG, c.getName() + " " + c.getId());
                add(c);
                notifyDataSetChanged();
            }
        } else {
            Log.e(TAG, "Empty Filter");
            notifyDataSetChanged();
        }
    }
};

然后我开始四处浏览，发现这行始终为空Log.e("Sta" + TAG, customer.getName()); //This is always null Log.e("Sta" + TAG, customer.getName()); //This is always null行Log.e("Cons " + TAG, constraint.toString()); Log.e("Sta" + TAG, customer.getName()); //This is always null 这行Log.e("Ite "+TAG, "" + itemsAll.size()); 永远不会为空。 除非没有传递任何文本，否则约束不能肯定为null。 但是，如果itemsAll.size()不为null或为空，则第一个对象为null。 我很困惑。 下面是我的List初始化

private static final String TAG = "StateAdapter";
private ArrayList<State> items;
private ArrayList<State> itemsAll;
private ArrayList<State> suggestions;
private Context context;
private int viewResourceId;

public StateAutoCompleteAdapter(Context context, int resource, int textViewResourceId, ArrayList<State> objects) {
    super(context, resource, textViewResourceId, objects);
    this.context = context;
    this.items = objects;
    this.itemsAll = new ArrayList<State>(items);
    this.suggestions = new ArrayList<State>();
    this.viewResourceId = resource;
}

而对于getView函数

public View getView(int position, View convertView, ViewGroup parent) {
    View v = convertView;
    if (v == null) {
        LayoutInflater vi = (LayoutInflater) getContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        v = vi.inflate(viewResourceId, null);
    }
    State customer = items.get(position);
    if (customer != null) {
        TextView customerNameLabel = (TextView) v.findViewById(R.id.bakerName);
        TextView bakerAddress = (TextView) v.findViewById(R.id.bakerAddress);
        if (customerNameLabel != null) {
//              Log.i(MY_DEBUG_TAG, "getView Customer Name:"+customer.getName());
            customerNameLabel.setText(customer.getName());
            bakerAddress.setVisibility(View.GONE);
        }
    }
    return v;
}

Answer 1

因此，我自己解决了此问题。 所以，我用一个正常的BaseAdapter和延长Filterable因此，对于那些可能需要如何使用RealmDB与AutoCompleteTextView你去那里

 public class LgasAutoCompleteAdapter extends BaseAdapter implements Filterable {

private static final String TAG = "LgasAutoComp";
private Context mContext;
private List<Lga> mResult = new ArrayList<>();
private LayoutInflater inflater;

public LgasAutoCompleteAdapter(Context mContext) {
    this.mContext = mContext;
}

@Override
public int getCount() {
    return mResult.size();
}

@Override
public Object getItem(int position) {
    return mResult.get(position);
}

@Override
public long getItemId(int position) {
    return position;
}

@Override
public View getView(int position, View view, ViewGroup parent) {
    if (inflater == null)
        inflater = (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);

    if (view == null)
        view = inflater.inflate(R.layout.item_baker_autocomplete, parent, false);

    Lga lga = mResult.get(position);

    TextView customerNameLabel = (TextView) view.findViewById(R.id.bakerName);
    TextView bakerAddress = (TextView) view.findViewById(R.id.bakerAddress);

    if (lga != null) {
        if (customerNameLabel != null) {
//              Log.i(MY_DEBUG_TAG, "getView Customer Name:"+customer.getName());
            customerNameLabel.setText(lga.getName());
            bakerAddress.setVisibility(View.GONE);
        }
    }

    return view;
}

@Override
public Filter getFilter() {
    return new Filter() {
        @Override
        protected FilterResults performFiltering(CharSequence charSequence) {
            return null;
        }

        @Override
        protected void publishResults(CharSequence constraint, FilterResults filterResults) {
            if (constraint != null) {
                //String query = constraint.toString().toLowerCase();
                mResult = filterStates(constraint.toString());
                Log.e(TAG, ""+mResult.size());
                notifyDataSetChanged();
            } else {
                notifyDataSetInvalidated();
            }
        }
    };
}

@NonNull
private List<Lga> filterStates(String query) {
    Realm mRealm = RealmUtils.getRealmInstance(mContext);
    return mRealm.where(Lga.class)
            .contains("name", query)
            .or()
            .beginsWith("name", query)
            .findAll();
}
}

Answer 2

clear（）方法可能会引起问题。 因此，请检查您要清洗的阵列列表的代码。

另一个问题是因为您使用的是State customer = items.get(position); 在getView()并使用getView() suggestions.add(customer); 在performFiltering(CharSequence constraint)

希望这可以帮助。