通过PHPMailer将电子邮件发送到MySQL上的单个电子邮件地址

Question

“搜索结果”将显示一个表格，并且在每一行的末尾都有一个“电子邮件按钮”。 访客单击一个“电子邮件按钮”，系统将电子邮件发送给该注册的“用户”。

PHPMailer和邮件系统运行良好，但仅适用于静态电子邮件！

问题：我需要更改代码以将电子邮件发送给访客选择的单个电子邮件。 我在$query添加了“ WHERE”条件，但它似乎没有影响。

以下两行的通信功能正在起作用

$mail->AddAddress("support@domain.co.uk", "John Doe");
$mail->AddAddress("admin@domain.co.uk");

与以下行不工作

$mail->AddAddress("$email", "John Doe");

错误消息说：

“无效的地址：无法发送消息。”
“邮件错误：您必须提供至少一个收件人电子邮件地址。”

 <?php

//mailer.php

$dbhost = 'xxx.xxx.xxx.xxx'; 
$dbuser = 'user_name';
$dbpass = 'password';  
$dbtable = 'tablename';
$db = 'db_name';

$conn = mysqli_connect($dbhost,$dbuser,$dbpass,$db) or
die("Could not connect: " . mysql_error());
mysqli_select_db($conn,$db);

if(isset($_POST['requestedEmail'])){
    $requestedEmail = $_POST['requestedEmail'];
    }

//Connecting to database
$link = mysqli_connect($dbhost, $dbuser, $dbpass, $db) OR DIE ("Unable to connect to database! Please try again later.");
mysqli_select_db($conn,$db);

//Fetching from database table.
$query = "SELECT email FROM db_name WHERE email='". $requestedEmail . "'";

if ($result) 
{
while ($row = mysqli_fetch_array($result)) {
  send_mail($row['email']);
}
}
//$email = $row['email']; 
?>




<?php
  require 'PHPMailer_5.2.0/class.phpmailer.php';

  $email = $row['email'];      

  $mail = new PHPMailer();

$mail->IsSMTP();                                 // set mailer to use SMTP
$mail->Host = "domainname.co.uk;domainname.co.uk";  // specify main and back`enter code here`up server
$mail->SMTPAuth = true;     // turn on SMTP authentication
$mail->Username = "support@domain.co.uk";  // SMTP username
$mail->Password = "password"; // SMTP password

$mail->From = "support@domain.co.uk";
$mail->FromName ="Company Name";
$mail->AddAddress($email, "John Doe");

$mail->AddReplyTo("info@domain.co.uk", "Information"); 

$mail->WordWrap = 50;                                 // set word wrap to 50 characters
$mail->IsHTML(true);                                  // set email format to HTML

$mail->Subject = "Here is the subject 3.4";
$mail->Body    = "This is the HTML message body <b>in bold!</b>";
$mail->AltBody = "This is the body in plain text for non-HTML mail clients";

if(!$mail->Send())
{
 echo "Message could not be sent. <p>";
 echo "Mailer Error: " . $mail->ErrorInfo;
 exit;
}

echo "Message has been sent to: " . $email; // $email is not printed out
?>

Answer 1

这似乎是错误的

$query = "SELECT email FROM db_name WHERE email=$row[email]";

它从哪里获得$ row [email]？ 您需要在其中有一个有效的变量-例如在post数组中（假设您正在从表单传递变量。类似：

if(isset($_POST['requestedEmail'])){
$requestedEmail = $_POST['requestedEmail']}
// other code

$query = "SELECT email FROM db_name WHERE email='". $requestedEmail . "';

然后，您从返回的$ row中获取电子邮件（假设您正在使用返回查询中的该变量）

$email = $Row['email'];

然后，您可以使用$ email（不带引号，因为它是变量而不是字符串）：

$mail->AddAddress($email, "John Doe");

Answer 2

这行：

$mail->AddAddress("$email", "John Doe");

应更改为：

$mail->AddAddress($email, "John Doe");

在PHP中将变量作为参数传递时，不要像在传递字符串时那样在变量周围使用引号。 因此，在您的代码中，您没有传递变量$ email，而是传递了字符串“ $ email”。