[英]How to sort an associative array by sort function in Javascript with the same ID?
function updateUld(pUldValues){
if (pUldValues != null){
pUldValues.sort(compareSort);
}
}
function compareSort (first,second){
var ret = 0;
var uldA = first[1]; //TOTO
var UldB = second[1]; //MAMA
if (uldA.substring(0,1) == "T"){
ret = compareRefUldRefUldTULD(uldA, UldB);
}
if (uldA.substring(0,1) == "M" ||
uldA.substring(0,1) == "A"){
ret = compareRefUldRefUldMix(uldA, UldB);
}
if (uldA.substring(0,1) == "L"){
ret = compareRefUldRefUldLoose(uldA, UldB);
}
if(ret==0){
if (UldB.substring(0,1) == "M" ||
UldB.substring(0,1) == "A"||
UldB.substring(0,1) == "T" ||
UldB.substring(0,1) == "L"){
ret = -1 ;
}else{
ret= UldB.localeCompare(uldA);
}
}
return -ret ;
}
pUldValues
前的pUldValues
包含555 : MAMA + 556 : TOTO
...
排序后是: 0 : TOTO + 1 : MAMA
...
我希望我有相同的排序,但采用这种格式: 555 : TOTO + 556 : MAMA
您不能将 Array 用作 Map,也不能订购 Object。
但是从 ECMAScript 2015 开始,您可以使用Map对象来保证键的顺序。 查看地图文档
这是一个输入对象的快速示例:
var myMap = { "555": "TOTO", "556": "MAMA", "557": "PAPA", "1": "ZOE", "2": "ABC" }; function sortMap(map){ // Get the keys of map var keys= Object.keys(map); // Sort the keys by the value keys.sort(function(a,b){ var aValue = map[a]; var bValue = map[b]; if(aValue < bValue) return -1; if(aValue > bValue) return 1; return 0; }); // Rebuild the map from the sorted key. var result = new Map; for(var i = 0; i < keys.length; i++){ result.set(keys[i], map[keys[i]]); } return result; } var sortedMap = sortMap(myMap); // Snipet display sortedMap.forEach(function(value, key){ document.body.appendChild(document.createElement('div')).innerHTML = key+'=>'+value; });
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