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[英]Type is an interface or abstract class and cannot be instantiated. c# send a object with contain a list of abstract object
[英]C# JSON Deserialization : Type is an interface or abstract class and cannot be instantiated
我正在使用这个C#项目,该项目使用API与在线交易平台Poloniex进行通信 。
此代码应该在钱包中获得余额:
var x = await polo_client.Wallet.GetBalancesAsync();
虽然此代码提供此错误:
获取钱包时出错:无法创建Jojatekok.PoloniexAPI.WalletTools.IBalance类型的实例。
Type是接口或抽象类,无法实例化。
路径'1CR.available',第1行,第20位。
在Helper.cs这里:
[SuppressMessage("Microsoft.Usage", "CA2202:Do not dispose objects multiple times")]
internal static T DeserializeObject<T>(this JsonSerializer serializer, string value)
{
using (var stringReader = new StringReader(value))
{
using (var jsonTextReader = new JsonTextReader(stringReader))
{
return (T)serializer.Deserialize(jsonTextReader, typeof(T));
}
}
}
调用它的代码是:
public T GetData<T>(string command, params object[] parameters)
{
var relativeUrl = CreateRelativeUrl(command, parameters);
var jsonString = QueryString(relativeUrl);
var output = JsonSerializer.DeserializeObject<T>(jsonString);
return output;
}
有人能告诉我为什么我在反序列化这个JSON响应时出错了吗?
响应是JSON,以下是它的示例:
{
"1CR":{"available":"0.00000000","onOrders":"0.00000000","btcValue":"0.00000000"},
"ABY":{"available":"0.00000000","onOrders":"0.00000000","btcValue":"0.00000000"}
}
是不是JSON,错误是自我描述的。 您无法实例化接口或抽象类。 它们只是他们所代表的功能或对象结构的蓝图。
例如,你不能这样做:
var something = new ISomething();
但是,你可以这样做:
ISomething something = new Something();
您只需要该接口的一些具体实现。 就像是:
public JsonReceived : IBalance
{
// rest of the implementation
}
或者可能已由第三方提供,请检查其SDK文档。
这就是我为使其工作所做的工作。 感谢来自Guru.com的Chris让这个工作。 伟大的家伙,非常好的价格。 你可以在这里找到他: http : //www.guru.com/freelancers/deatc
private IDictionary<string, IBalance> GetBalances()
{
var postData = new Dictionary<string, object>();
var data = PostData<IDictionary<string, Balance>>("returnCompleteBalances", postData);
var returnData = new Dictionary<string, IBalance>();
foreach (string key in data.Keys)
{
returnData.Add(key, data[key]);
}
return returnData;
}
由于对象的DeSerialization导致的错误,内部创建一个Jobject并将其作为输入Generic投射,在上面的场景中,因为我们无法创建一个Interface的对象,所以它抛出一个错误,我们可以通过以下方式实现根据您在GitHub中发布的解决方案
IBalance CreateFactory(string typeOfBalance, string jsonString) { IBalance balance = null; switch (typeOfBalance) { case "balanceClassIdentification": balance = new Balance(); balance = Newtonsoft.Json.JsonConvert.DeserializeObject<Balance>(jsonString); break; case "": // write logic if Ibalance interface implemented in any childClass ex: class stockBalance: IBalance , then balance = new StockBalance();balance = Newtonsoft.Json.JsonConvert.DeserializeObject<stockBalance>(jsonString); default: balance = new Balance(); balance = Newtonsoft.Json.JsonConvert.DeserializeObject<Balance>(jsonString); break; } return balance; } private IDictionary<string, IBalance> GetBalances() { IDictionary<string, IBalance> data = null; var postData = new Dictionary<string, object>(); //var data = PostData<IDictionary<string, object>>("returnCompleteBalances", postData); Hashtable output = PostData<Hashtable>("returnCompleteBalances", postData); if (output.Count > 0) { data = new Dictionary<string, IBalance>(); } foreach (string jsonObjKey in output.Keys) { IBalance balace = CreateFactoty("balanceClassIdentification", output[jsonObjKey].ToString()); // this "balanceClassIdentification" just used as a string but we can add the condition in createFactory according to the type of object that wallet data.Add(jsonObjKey, balace); } return data; }
public class BalanceBase: IBalace { }
需要改变平衡等级
private IDictionary<string, Balance> GetBalances()
{
var postData = new Dictionary<string, object>();
var data = PostData<IDictionary<string, Balance>>("returnCompleteBalances", postData);
return data;
}
private IDictionary<string, Balance> GetBalances() { var postData = new Dictionary<string, object>(); var data = PostData<IDictionary<string, Balance>>("returnCompleteBalances", postData); return data; }
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