[英]What's wrong with my AJAX/HTML/PHP code to add to my SQL database?
[英]My php is not entering the values into the sql database, what is wrong with my code?
我有一个注册表并且使用 PHP 和 MySQL 时遇到了这个问题。 问题是即使所有数据都有效,它也不会将信息输入数据库。 我知道数据库已连接,因为我可以将它与我网站的登录部分一起使用。 我认为这是针对数据库的电子邮件和用户名交叉检查的问题,但我不确定。 花括号的位置是更复杂还是更复杂?
<?php
include_once('db.php');
$name = mysql_real_escape_string( $_POST["name"] );
$username = mysql_real_escape_string( ($_POST["username"]) );
$password = mysql_real_escape_string( md5 ($_POST["password"]) );
$repeatpassword = mysql_real_escape_string( $_POST['repeatpassword'] );
$email = mysql_real_escape_string( $_POST["email"] );
$confirmemail = mysql_real_escape_string( $_POST['confirmemail'] );
// the below if statement is for when the user does NOT have JS enabled in their browser
if(empty($name) || empty($username) || empty($password) || empty($email)){
echo "(*) indicate that the fields are mandatory.";
exit();
}
if($email == $confirmemail){
exit();
}else{
echo "Your Email address does not match.";
}
if($email == $repeatpassword){
exit();
}else{
echo "Your Passwords do not match.";
exit();
}
$res = mysql_query("SELECT username FROM users WHERE username='$username'");
$row = mysql_fetch_row($res);
$res1 = mysql_query("SELECT email FROM users WHERE email='$email'");
$row1 = mysql_fetch_row($res1);
if( $row > 0 ){
echo nl2br("The username $username is already in use");
}else{
if( $row1 > 0 ){
echo nl2br("the email address $email is already in use");
}else{
$sql = "INSERT INTO users VALUES('','$name', '$username', '$password', '$email')";
if( mysql_query($sql) ){
echo "Inserted Successfully";
}else{
echo "Insertion Failed";
}
}
}
?>
if($email == $confirmemail) {
exit();
}
else {
echo "Your Email address does not match.";
}
因此,您在上面的代码中所做的是“如果电子邮件和确认电子邮件相同,则停止脚本执行,否则打印出'您的电子邮件地址不匹配。' 并继续执行”。
if ($email == $repeatpassword) {
exit();
}
else {
echo "Your Passwords do not match.";
exit();
}
在这里你是说如果“电子邮件和重复密码相同(???),停止脚本执行,否则打印出'你的密码不匹配。' 并停止脚本执行”。
因此,显然由于这种逻辑,您永远不会到达将数据插入数据库的代码。
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