使用 Android Volley 发送 JSON Post with Body

Question

我正在尝试使用 Android Volley 库发送 JSON Post 请求，但我似乎没有正确获取 json 的主体，并且在我的 web 服务器上获得未定义的主体参数。 我需要 json 的参数主体是单个 object“name=someVal&comment=someOtherVal”。 name 和 comment 是键，someVal 和 someOtherVal 是值。

String spreadsheetID = "1111111-11111N92RT9h-11111111111111111111111111111";
String url = "https://script.google.com/macros/s/" + spreadsheetID + "/exec";
// Instantiate the RequestQueue.
RequestQueue queue = Volley.newRequestQueue(this);

// Request a string response from the provided URL.
JsonObjectRequest jsonObjReq = new JsonObjectRequest(Request.Method.POST,
        url, null,
        new Response.Listener<JSONObject>() {

@Override
public void onResponse(JSONObject response) {
    Log.d("JSONPost", response.toString());
    //pDialog.hide();
}
        }, new Response.ErrorListener() {

    @Override
    public void onErrorResponse(VolleyError error) {
        VolleyLog.d("JSONPost", "Error: " + error.getMessage());
        //pDialog.hide();
    }
}) {

    @Override
    protected Map<String, String> getParams() {
        Map<String, String> params = new HashMap<String, String>();
        params.put("name=someVal&comment=someOtherVal");
        //params.put("comment", "someOtherVal");
        return params;
    }
};
// Add the request to the RequestQueue.
queue.add(jsonObjReq);

}

我也在上面的代码中尝试过这个但没有运气：

params.put("comment", "someOtherVal");
params.put("name", "someVal");

Answer 1

试着把

Map<String, String> params = new HashMap<String, String>();
params.put("comment", "someOtherVal");
params.put("name", "someVal");

在JsonObjectRequest之前jsonObjReq ...并更改null值

new JsonObject(params)

所以你的代码将是

Map<String, String> params = new HashMap<String, String>();
    params.put("comment", "someOtherVal");
    params.put("name", "someVal");

JsonObjectRequest jsonObjReq = new JsonObjectRequest(Request.Method.POST,
        url, new JsonObject(params),
        new Response.Listener<JSONObject>() {

@Override
public void onResponse(JSONObject response) {
    Log.d("JSONPost", response.toString());
    //pDialog.hide();
}
        }, new Response.ErrorListener() {

    @Override
    public void onErrorResponse(VolleyError error) {
        VolleyLog.d("JSONPost", "Error: " + error.getMessage());
        //pDialog.hide();
    }
})

Answer 2

谷歌电子表格似乎更喜欢这种格式：

String spreadsheetID = "111111-111111111D746wspoleBbRN92RT9h-111111";
        String url = "https://script.google.com/macros/s/" + spreadsheetID + "/exec";
        // Instantiate the RequestQueue.
        RequestQueue queue = Volley.newRequestQueue(this);

        StringRequest sr = new StringRequest(Request.Method.POST,url, new Response.Listener<String>() {
            @Override
            public void onResponse(String response) {
                //
            }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                //
            }
        }){
            @Override
            protected Map<String,String> getParams(){
                Map<String,String> params = new HashMap<String, String>();
                params.put("name","userAccount.getUsername()");
                params.put("comment","userAccount.getPassword()");
                return params;
            }

            @Override
            public Map<String, String> getHeaders() throws AuthFailureError {
                Map<String,String> params = new HashMap<String, String>();
                params.put("Content-Type","application/x-www-form-urlencoded");
                return params;
            }
        };
        queue.add(sr);

Answer 3

如果你需要发送一个JSON POST，你应该转储http.HEADERS和http.WIRE，你应该看到....

 "Content-Type: application/json"   // among headers
...
   {"name":"someVal","comment":"someOtherVal"}   // in the POST.body 

了解如何在Volley中记录标题和日志线....

考虑在CLI上使用CURL测试POST，添加-v开关将显示详细信息。 那么，什么在curl中你可以逐字地移动到你的android，http客户端，它会工作。

Answer 4

这对我有用，我正在向使用 express.json() 的 Express 服务器发送请求。 我在正文中发送的 object 称为用户，如下所示：

{ 
   String: username;
   String: password; 
}

 RequestQueue queue = Volley.newRequestQueue(this);
 
 // user object that we need to send
 JSONObject userJson = new JSONObject();
 // body of the request
 JSONObject body = new JSONObject();

 try {
    // Put user attributes in a JSONObject
    userJson.put("username", "username value");
    userJson.put("password", "password value");
    // Put user JSONObject inside of another JSONObject which will be the body of the request     
    body.put("user", userJson);
 } catch (JSONException e) {
    e.printStackTrace();
 }

JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(
                    Request.Method.POST, 
                    url, 
                    body,
                    response -> {
                        // Handle response
                        
                    }, e -> {
                        // handle error
                    }
);

 queue.add(jsonObjectRequest);