[英]Grouping SQL results by Year and count
它的一部分正在发展。 行和列的总计(实际上甚至是透视)都应在报表应用程序中完成,而不是在SQL中完成。 如果您坚持要使用SQL进行操作,则可以使用更简便的方法,但是下面的一些愚蠢的查询就足够了。
with test_data (city, yr, ct) as (
select 'Tokyo' , 2016, 2 from dual union all
select 'Mumbai', 2013, 3 from dual union all
select 'Mumbai', 2014, 5 from dual union all
select 'Dubai' , 2011, 5 from dual union all
select 'Dubai' , 2015, 15 from dual union all
select 'Dubai' , 2016, 8 from dual union all
select 'London', 2011, 16 from dual union all
select 'London', 2012, 22 from dual union all
select 'London', 2013, 4 from dual union all
select 'London', 2014, 24 from dual union all
select 'London', 2015, 13 from dual union all
select 'London', 2016, 5 from dual
),
test_with_totals as (
select city, yr, ct from test_data union all
select city, 9999, sum(ct) from test_data group by city union all
select 'Grand Total', yr , sum(ct) from test_data group by yr union all
select 'Grand Total', 9999, sum(ct) from test_data
)
select * from test_with_totals
pivot ( sum (ct) for yr in (2011, 2012, 2013, 2014, 2015, 2016, 9999 as "Total"))
order by "Total";
结果:
CITY 2011 2012 2013 2014 2015 2016 Total
----------- ---------- ---------- ---------- ---------- ---------- ---------- ----------
Tokyo 2 2
Mumbai 3 5 8
Dubai 5 15 8 28
London 16 22 4 24 13 5 84
Grand Total 21 22 7 29 28 15 122
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.