OrientDB从多个Edge中选择唯一的顶点

Question

我有2个顶点User和Stamp。 顶点由Have，WishToHave和Selling三个边缘关联。

我希望选择与用户有任何关系的独特图章。 为此，我正在运行以下命令：

select expand(out('Have', 'WishToHave', 'Selling')) from #12:0

该命令的问题在于它会多次返回“ Stamp1”，因为它具有“销售”和“销售”优势。

如何选择与User1相关的所有唯一/不同图章？

要为该示例初始化测试数据：

create class User extends V
create class Stamp extends V

create class Have extends E
create class WishToHave extends E
create class Selling extends E

create vertex User set name = 'User1'
create vertex Stamp set name = 'Stamp1'
create vertex Stamp set name = 'Stamp2'
create vertex Stamp set name = 'Stamp3'


create edge Have from (select from User where name = 'User1') to (select from Stamp where name = 'Stamp1')
create edge WishToHave from (select from User where name = 'User1') to (select from Stamp where name = 'Stamp2')
create edge Selling from (select from User where name = 'User1') to (select from Stamp where name = 'Stamp1')
create edge Selling from (select from User where name = 'User1') to (select from Stamp where name = 'Stamp3')

Answer 1

我尝试过使用您的结构的情况：

要检索唯一的顶点，可以使用DISTINCT()函数。 我可以举两个例子：

查询1：在目标查询中使用EXPAND()

SELECT EXPAND(DISTINCT(@rid)) FROM (SELECT EXPAND(out('Have', 'WishToHave', 'Selling')) FROM #12:0)

输出：

查询2：在目标查询中使用UNWIND

SELECT EXPAND(DISTINCT(out)) FROM (SELECT out('Have', 'WishToHave', 'Selling') FROM #12:0 UNWIND out)

输出：

希望能帮助到你