上传使用curl php POST参数丢失

Question

嗨我想使用curl在codeigniter中将文件上传到服务器我在视图中设置表单并传递给控制器​​并使用curl在控制器上传它但它显示错误

缺少POST参数issue_identifier我不知道是什么导致了这个问题

这是我的控制器

  $issue_name = $this->input->post('issue_name');
  $issue_tagline = $this->input->post('issue_tagline');
  $issue_description = $this->input->post('issue_description');
  $issue_publish_on = $this->input->post('issue_publish_on');
  $issue_file = $this->input->post('issue_file');
  $issue_id = $this->input->post('issue_id');

$data2=array(
  'imgdetail'=>$imgdetail ,
  'username' =>$session_data['username'],
  'appname'=> $this->appname,
  'mode'=> $this->mode,
  'appidentifier'=> $this->appidentifier,
  'name' => $name,
  'productid' => $productid,
  'status'=>$status,
  'description'=>$description,
  'issue_name' => $issue_name,
  'issue_tagline' => $issue_tagline,
  'issue_description' => $issue_description,
  'issue_file' => $issue_file,
 ); 

$this->load->helper('form');
$this->load->view('issue_detail',$data2);


  echo '<pre>' .var_dump($issue_name).'</pre>';
  echo '<pre>' .var_dump($productid).'</pre>';
  echo '<pre>' .var_dump($issue_id).'</pre>';

  $target_url = 'https://platform.twixlmedia.com/admin-api/1/upload';

  $file_name_with_full_path = realpath($issue_file);
  $post3 = array(
'admin_api_key'    => 'da06751194bc18cc60xxxxxxxxxxxx',
'app_key'          => 'bd7cf04226c58723cac4xxxxxxxxx',
'issue_identifier' => $issue_id,
'issue_file'       =>'@' . realpath($issue_file),
'issue_name'       => $issue_name
  );

$ch3 = curl_init();
curl_setopt($ch3, CURLOPT_URL, 'https://platform.twixlmedia.com/admin-api/1/upload');
curl_setopt($ch3, CURLOPT_POST, 1);
curl_setopt($ch3, CURLOPT_POSTFIELDS, http_build_query($post3));
curl_setopt($ch3, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch3, CURLOPT_SSL_VERIFYPEER, false);
$result3 = curl_exec($ch3);
curl_close ($ch3);
echo $result3;

这是我的看法：

            <form class="editissueform" action="home/detail_issue" method="post" enctype="multipart/form-data">
            <label for="name">Name:</label>
            <input type="text" name="issue_name"><br>
            <label for="tagline">Tagline:</label>
            <input type="text" name="issue_tagline"><br>
            <label type"description">Description:</label>
            <input type="text" name="issue_description"><br>
            <label type"publishdate">Publish Date:</label>
            <input type="text" name="issue_publish_on"><br>

        </div>
        <h4>Upload Publication</h4>
        <div class="issuedit">

            <input type="file" name="issue_file" size="40" />
            <h7>Please Upload using pdf file format</h7>

        </div>
        <br>
        <br>
        <input type="submit" name="submit" value="Save">
        </form>  

谢谢你的帮助

Answer 1

看起来你的另一端正在向你发回错误，而错误似乎意味着你没有用你的POST请求发布“issue_id”。

$issue_id = $this->input->post('issue_id');

这就是你获取“issue_id”的方法，但是当我查看你的表单时，我没有在那里看到那个字段，这意味着它将为null或为空。

为您的curl请求提供另一端理解的有效“issue_id”，我认为您已完成。