从表格中获取最新的两个不同位置

Question

下面是我的桌子，

从表名WHERE user_id ='8'中选择DISTINCT（availability_location）作为位置ORDER BY Availability_date DESC LIMIT 2

我得到以下结果

我想要以下结果：

2016-05-27浦那

2016-05-20伯班克

即唯一的availability_location以及最近的两个条目。

Answer 1

您必须为此使用GROUP BY ：

SELECT availability_location as location,
       MAX(availability_date) AS max_date
FROM table_name 
WHERE user_id = '8' 
GROUP BY location
ORDER BY max_date DESC LIMIT 2

Answer 2

您可以使用GROUP BY并按最大日期排序：

 SELECT t.availability_location
 FROM table_name t 
 WHERE user_id = '8'
 GROUP BY t.availability_location 
 ORDER BY max(s.availability_date) DESC LIMIT 2

输出：

availability_location
---------------------
pune
Burbank

编辑：下次，您应该提到您希望它区分大小写。 您可以尝试这样做：

 SELECT t.availability_location 
 FROM table_name t 
 INNER JOIN(SELECT s.availability_location , max(s.availability_date) as max_d
            FROM table_name s
            WHERE s.user_id = '8'
            GROUP BY s.availability_location) t2
  ON(t2.availability_location = t.availability_location AND
     t2.max_d = t.availability_date)
 ORDER BY t.availability_date DESC LIMIT 2