网址与 web.xml 中的网址模式不匹配

Question

在 web.xml 文件中，我有这个 url 模式：

<url-pattern>/servletPrueba/*</url-pattern>

在jsp文件中，我有这个链接：

<a href="servletPrueba/a">Enlace servlet</a>

但是我收到 404 错误，我认为 url 与 url 模式匹配，不是吗？

这是servlet，它只是一个测试用途的servlet，仅供练习

package pruebas;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 * Servlet implementation class servletPrueba
 */
//@WebServlet("/servletPrueba")
public class servletPrueba extends HttpServlet {
    private static final long serialVersionUID = 1L;

    /**
     * @see HttpServlet#HttpServlet()
     */
    public servletPrueba() {
        super();
        // TODO Auto-generated constructor stub
    }

    /**
     * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        // TODO Auto-generated method stub
        //response.getWriter().append("Served at: ").append(request.getContextPath());
        RequestDispatcher despachador = null;
        String ruta = request.getPathInfo();    
        PrintWriter out = response.getWriter();
        out.println(request.getPathInfo());
        out.println(request.getServletPath());


    }

    /**
     * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        // TODO Auto-generated method stub
        //doGet(request, response);
        PrintWriter out = response.getWriter();
        out.println("POST");
    }

}

webb.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1">
  <display-name>pruebas</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>

  <servlet>
    <servlet-name>servletPrueba</servlet-name>
    <servlet-class>pruebas.servletPrueba</servlet-class>
  </servlet>

  <servlet-mapping>
    <servlet-name>servletPrueba</servlet-name>
    <url-pattern>/servletPrueba/*</url-pattern>
  </servlet-mapping>
</web-app>

Answer 1

这是一个完整的示例（我没有使用 Maven，但是我可以）：