[英]How to bind through collection?
如何通过列表匹配值? 就我而言,我有一个颜色列表-
["Black", "Lavender", "Brazen", "Army", "Birch"]
我有此函数可创建颜色名称和相关URL的集合:
(combine-color-imgurl get-product-images)
=>
[("Black"
"example.com/WWbNhro1n3YfmQTx1q5Piv1j8lZzse6M-25_2a353315-9965-457f-83f8-32af89f3b067.jpeg")
("Lavender"
"example.com/trWCTNYNOfiA8EBX9HZcxVB1Hg8pVtr9-25_403cbe3e-9894-4ad6-9f69-dedcfd7ef77b.jpeg")
("Brazen"
"example.com/COYrBHEsiOgdeOfxsQGcw8XXynsVdpxy-25_af0a9ff9-b988-467e-9b39-c4ae572420e8.jpeg")
("Army"
"example.com/YWKhJXFM0dKhJuRXphCXD4TWstnZRRJm-25_b3a2e43c-3c8c-4abc-83d2-d00d9b3ed594.jpeg")
("Birch"
"example.com/IRsHVjavdFsybvmpT6xjnpKqMtjyjeoZ-25_6321e4ef-5bed-463f-990a-1857151b8a11.jpeg")]
我不确定如何仅获取与颜色相关的网址。
所以功能会像
(defn get-url [color]
(some-operation (combine-color-imgurl get-product-images)))
=> URL
正如Juan所提到的,解决方案是让combine-color-imgurl
返回地图然后使用
(get (into {} (combine-color-imgurl get-product-images)) color)
获取URL。
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