一种形式中有多个图像输入？

Question

我看到的大多数问题都与一个图像输入有关。 但是，如果您拥有2或3或更多，该怎么办？

我的一个图像输入脚本起作用，但是我试图在表单中包含一个单图像输入和一个多图像输入。 我正在测试在表单上有2个单图像输入，但无法正常工作。

这是一个单图像输入的HTML（假设它在<form>标记内）：

  <input type="hidden" name="size" value="350000"/>
  <input type="file" name="schoollogo"/><br/>

PHP：

  $target = "images/logo/";
  $target = $target . basename( $_FILES['schoollogo']['name']);

  $schoollogo = $_FILES['schoollogo']['name'];

  //Writes the information to the database

  mysql_query("INSERT INTO Colleges (schoollogo) VALUES ('$schoollogo')") or die(mysql_error()) ;

  //Writes the logo to the server
  if (move_uploaded_file($_FILES['schoollogo']['tmp_name'], $target)) {
      //Tells you if its all ok
      echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";
  } else {
      //Gives and error if its not
      echo "Sorry, there was a problem uploading your file.";
  }

对于第二个单图像输入，我刚刚添加了第二个输入代码...

 <input type="hidden" name="size" value="350000"/>
 <input type="file" name="otherimage"/><br/>

然后将变量添加到PHP：

  $targetotherimage = "images/otherimage/";
  $targetotherimage = $targetotherimage . basename( $_FILES['otherimage']['name']);

  mysql_query("INSERT INTO Colleges (schoollogo,otherimage) VALUES ('$schoollogo','$otherimage')") or die(mysql_error()) ;

  //Writes the logo to the server
  if (move_uploaded_file($_FILES['schoollogo']['tmp_name'], $target)) && (move_uploaded_file($_FILES['otherimage']['tmp_name'], $targetotherimage)) {

但是，当将该代码添加到PHP中时，该代码将无法工作。 没有错误消息或任何东西。 页面为空白。

顺便说一句， 这是我的另一个问题 ，我正在尝试将一个多图像上传输入与一个已经正常工作的单图像上传输入添加到表单中。

Answer 1

错误关闭if条件。

  if(move_uploaded_file($_FILES['schoollogo']['tmp_name'], $target)) && (move_uploaded_file($_FILES['otherimage']['tmp_name'], $targetotherimage)) {
                                                                  ^^^^// In your code if condition close here

用作

  if(move_uploaded_file($_FILES['schoollogo']['tmp_name'], $target) 

&& (move_uploaded_file($_FILES['otherimage']['tmp_name'],  $targetotherimage)))//if condition close here 
{
// rest of code

}

Answer 2

这将为您工作，用此替换您的表格

<form method="post" enctype="multipart/form-data" action="upload.php">
      <input type="file" name="file['schoollogo']" >
      <input type="file" name="file['otherimage']" >
      <input type="submit" value="submit">
</form>

您将以以下格式获取文件：

Array
(
    [file] => Array
        (
            [name] => Array
                (
                    ['schoollogo'] => 1465386599_Location_Outline-36.png
                    ['otherimage'] => STONE_Website_v7E.jpg
                )

            [type] => Array
                (
                    ['schoollogo'] => image/png
                    ['otherimage'] => image/jpeg
                )
        ) 
) 

并在upload.php文件中

<?php 
if (isset($_FILES['file'])) 
{
     $schoollogo=$_FILES['file']['name']['schoollogo'];
     $target = "images/logo/".basename($schoollogo);;

     $otherimage = $_FILES['file']['name']['otherimage'];
     $targetotherimage = "images/otherimage/".basename($otherimage);

      $tmp_name_school = $_FILES['file']['tmp_name']['schoollogo'];
      $tmp_name_other = $_FILES['file']['tmp_name']['otherimage'];

      if ($tmp_name_school != "" && $tmp_name_other !== "")
      {
        //Upload the file 
        if(move_uploaded_file($tmp_name_school,$target) && move_uploaded_file($tmp_name_other, $targetotherimage)) 
        {
          mysql_query("INSERT INTO Colleges (schoollogo,otherimage) VALUES ('$schoollogo','$otherimage')") or die(mysql_error()) ;
          echo'Done!';
        }
        else
        {
            echo "Not Moved";
        }
      }
}   
?>