从多个数据库导出表并导入到单个数据库

Question

我想从多个数据库中以相同的名称从三个表中导出特定数据，并将它们导入到单个数据库SUPPORT_DATABASE ，这些表是XXX_users ， XXX_usergroups ， XXX-user_usergroup_map 。

用户id是所有表中的主键。

这是我到目前为止拥有的脚本

MySQL-Export.php

<?php
//ENTER THE RELEVANT INFO BELOW
$mysqlDatabaseName ='db1';
$mysqlUserName ='db1owner';
$mysqlPassword ='Password';
$mysqlHostName ='db1.mywebhost.net';
$mysqlExportPath ='db1backup.sql';

//DONT EDIT BELOW THIS LINE
//Export the database and output the status to the page
$command='mysqldump --opt -h' .$mysqlHostName .' -u' .$mysqlUserName .' -p'    .$mysqlPassword .' ' .$mysqlDatabaseName .'
SELECT id, name, username, password, email FROM `xxx_users` WHERE `id` in (SELECT `user_id` FROM `xxx_user_usergroup_map` WHERE `group_id` = (SELECT `id`     FROM `xxx_usergroups` WHERE `title` = 'Administrator'));
SELECT id, name, username, password, email FROM `xxx_users` WHERE `id` in (SELECT `user_id` FROM `xxx_user_usergroup_map` WHERE `group_id` = (SELECT `id` FROM `xxx_usergroups` WHERE `title` = 'Engineer'));
> ~/' .$mysqlExportPath;
exec($command,$output=array(),$worked);
switch($worked){
case 0:
echo 'Database <b>' .$mysqlDatabaseName .'</b> successfully exported to <b>~/' .$mysqlExportPath .'</b>';
break;
case 1:
echo 'There was a warning during the export of <b>' .$mysqlDatabaseName .'</b> to <b>~/' .$mysqlExportPath .'</b>';
break;
case 2:
echo 'There was an error during export. Please check your values:<br/><br/><table><tr><td>MySQL Database Name:</td><td><b>' .$mysqlDatabaseName .'</b></td></tr><tr><td>MySQL User Name:</td><td><b>' .$mysqlUserName .'</b></td></tr><tr><td>MySQL Password:</td><td><b>NOTSHOWN </b></td></tr><tr><td>MySQL Host Name:</td><td><b>' .$mysqlHostName .'</b></td></tr></table>';
break;
}
?>

MySQL-Import.php

$mysqlDatabaseName ='db2';
$mysqlUserName ='db2owner';
$mysqlPassword ='Password';
$mysqlHostName ='db2.mywebhost.net';
$mysqlImportFilename ='db1backup.sql';

//DONT EDIT BELOW THIS LINE
//Export the database and output the status to the page
$command='mysql -h' .$mysqlHostName .' -u' .$mysqlUserName .' -p' .$mysqlPassword .' ' .$mysqlDatabaseName .' < ' .$mysqlImportFilename;
exec($command,$output=array(),$worked);
switch($worked){
case 0:
echo 'Import file <b>' .$mysqlImportFilename .'</b> successfully imported to    database <b>' .$mysqlDatabaseName .'</b>';
break;
case 1:
echo 'There was an error during import. Please make sure the import file is saved in the same folder as this script and check your values:<br/><br/><table><tr><td>MySQL Database Name:</td><td><b>' .$mysqlDatabaseName .'</b></td></tr><tr><td>MySQL User Name:</td><td><b>' .$mysqlUserName .'</b></td></tr><tr><td>MySQL Password:</td><td><b>NOTSHOWN</b></td></tr><tr><td>MySQL Host Name:</td><td><b>' .$mysqlHostName .'</b></td></tr><tr><td>MySQL Import Filename:</td><td><b>' .$mysqlImportFilename .'</b></td></tr></table>';
break;
}
?> 

表结构

XXX_user
user_id, name, username, email, password
300, john smtih, jsmith, jsmith@test.com, password123@

XXX_usergroups
group_id, type
8, administrator

XXX_user_group_map
user_id, group_id
300, 8

我想我能做的是，使用MySQL-Export.php从三个数据库中导出数据并将数据库存储在服务器上，然后使用MySQL-import.php所有三个数据库中的数据库导入辅助数据库，数据在这里MODIFY用户group_id中XXX-user_usergroup_map在匹配用户组SUPPORT_DATABASE

在这一点上，我有点卡住了，因为从多个数据库导入用户，该用户可能共享相同的user_id ，所以我不确定该怎么做，在哪里以及如何更改user_id 。

放在user_id上的SUPPORT_DATABASE上没有关系

任何人都可以提出一些建议吗？

Answer 1

这是一种逐步进行的方法

1. 使用此查询转储每个数据库

SELECT u.name, u.username, u.email, u.password, g2.type FROM "XXX_user" u, "XXX_user_group_map" g, "XXX_usergroups" g2 WHERE g.user_id = u.user_id AND g.group_id = g2.group_id

在此查询中，您将获得用户组类型作为字符串，可在其中用于与您的SUPPORT_DATABASE组ID匹配

2. 现在编写一个脚本以将sql导入SUPPORT_DATABASE ，将SUPPORT_DATABASE设置为在user_id上具有AUTO INCREMENT，在电子邮件上具有唯一性。