繁体   English   中英

如何提高mysql查询的性能?

[英]How to improve performance of mysql query?

我正在更新表中的多个行。 查询需要很长时间才能执行。 如何提高以下查询的执行性能?

update org_products op
inner join access_history
    on access_history.access_key = op.id and access_history.access_type = "OrgProduct.View"
set views =
(
    select count(access_key)
    from access_history
    where access_history.access_key = op.id and
          access_history.created_at >= DATE_SUB(CURDATE(), INTERVAL 90 DAY) and
          access_history.access_type = "OrgProduct.View" and
          access_history.product_id = op.product_id
    GROUP BY  access_history.product_id
)
where access_history.access_key = op.id and
      access_history.access_type = "OrgProduct.View";

更新:输出SHOW CREATE TABLE access_history;

 'access_history', 'CREATE TABLE `access_history` (
\n  `id` bigint(20) NOT NULL AUTO_INCREMENT,
\n  `product_id` bigint(20) unsigned NOT NULL,
\n  `access_type` varchar(50) DEFAULT NULL,
\n  `access_key` varchar(50) DEFAULT NULL,
\n  `access_key_full` varchar(200) DEFAULT NULL,
\n  `client_ip_addr` varbinary(16) DEFAULT NULL,
\n  `userid` bigint(20) unsigned DEFAULT NULL,\n  `username` tinytext,
\n  `anon_user_id` bigint(20) unsigned DEFAULT NULL,
\n  `created_at` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
\n  `updated_at` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,\n  PRIMARY KEY (`id`),
\n  KEY `fk_access_history_has_product_product1_idx` (`product_id`),
\n  KEY `idx_access_history_prod_type_key` (`product_id`,`access_type`,`access_key`),
\n  CONSTRAINT `fk_access_history_has_product_product1_idx` FOREIGN KEY (`product_id`) REFERENCES `products` (`id`) ON 
DELETE NO ACTION ON UPDATE NO ACTION\n) ENGINE=InnoDB AUTO_INCREMENT=1290353 DEFAULT CHARSET=utf8'

SHOW INDEX from access_history;输出SHOW INDEX from access_history; 在此输入图像描述

输出EXPLAIN query 在此输入图像描述

需要对查询进行哪些更改才能提高性能?

感谢任何帮助! 谢谢!

这里有2个变种:

1)您通过CRON定期执行讨论的查询 - 因此您希望更新在过去90天内访问历史记录已更改的所有产品。 尝试以下查询(您最好提前计算开始日期然后使用此常量值 - 使用DATE_SUB()将使MySQL认为这是一个动态值并且每次都会计算它,不会注意到它本质上是常数):

UPDATE org_products op
  SET views = (SELECT COUNT(*) FROM access_history
        WHERE access_key = op.id
            AND access_type = "OrgProduct.View"
    )
    WHERE op.id IN (SELECT access_key FROM access_history 
        WHERE access_type = "OrgProduct.View"
            AND created_at >= "YYYY-MM-DD"
    )

2)您在每次插入表access_history后执行讨论的查询 - 尝试以下(ACCESS_KEY_VALUE是您刚刚插入到表access_history中的内容 ):

UPDATE org_products op
    SET views = (SELECT COUNT(*) FROM access_history
        WHERE access_key = ACCESS_KEY_VALUE
            AND access_type = "OrgProduct.View"
    )
    WHERE op.id = ACCESS_KEY_VALUE

在这两种情况下,我建议您将列access_type中的所有不同字符串移动到单独的表中,将列转换为INT并使其成为该新表中的外键。 原因是索引和比较数值比比较字符串更快。

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM