[英]SQL count with decimal percentage breakdown - how do you limit to 4 decimal places?
我想将小数位更改为4,但无法弄清楚,请帮助!
-查询
select CASE v2.[ie version]
When '11' Then 'Internet Explorer 11'
When '9' Then 'Internet Explorer 9'
When '8' Then 'Internet Explorer 8'
Else [IE Version] End [IE Version],
COUNT(distinct v1.guid) 'Total Count', COUNT(*) *100.00 / SUM(COUNT(*)) over()'Total Percentage' from vcomputer v1
inner join vIEVersions v2 on v1.guid = v2.guid where v1.ismanaged = '1'
and v2.[IE Version] is not Null and v2.[IE Version] not in ('Unknown', '7', '10')
group by v2.[IE Version] order by 1 desc
-输出
IE Version Total Count Total Percentage
Internet Explorer 9 180 1.7349397590361
Internet Explorer 8 531 5.1180722891566
Internet Explorer 11 9664 93.1469879518072
我认为,首先您必须首先CREATE TABLE VIEW
小数百分比细分的CREATE TABLE VIEW
,然后再将round的值称为round函数,例如以下示例代码:
SELECT ROUND(column_name,decimals) FROM table_name;
希望能帮助到你。
CAST转换为十进制就足够了:
CAST(COUNT(*) *100.00 / SUM(COUNT(*)) over() as decimal(12,4))
试试这个,例如
声明@i int = 23
选择强制转换(@ i * 100.00 / 3作为十进制(10,4))
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.