MS SQL按行从另一个表复制数据

Question

我有以下2表：

DECLARE @table1 TABLE (
    [NO] int,
    A1 float, 
    A2 float, 
    A3 float, 
    A4 float, 
    A5 float,
    A6 float
)

DECLARE @table2 TABLE (
    KOD nvarchar(100), 
    ID_QUANTITY int
)

INSERT INTO @table1 VALUES
(1, 4.1, 3, 3.5, 23.5, 12.2, 2.4),
(2, 4.2, 0, 1.9, 34.5, 31.2, 34.2),
(3, 1.5, 0, 2.3, 12.3, 12.3, 1.2),
(4, 3.7, 2.1, 5.9, 4.8, 10.2, 21.2),
(5, 3.9, 2.6, 1.9, 12.3, 2.4, 10.2)

INSERT INTO @table2 VALUES
('A1', 500),
('A2', 600),
('A3', 700),
('A4', 800),
('A5', 900),
('A6', 1000)

而且我需要在sql中创建脚本以将第一个表中的值转换为如下所示

谢谢您的帮助

Answer 1

先取消UNPIVOT，然后加入，将ROW_NUMBER（）用于ID列：

SELECT  ROW_NUMBER() OVER (ORDER BY (SELECT 1)) as ID,
        ID_QUANTITY,
        [VALUES]
FROM (
    SELECT *
    FROM table1
    ) p
UNPIVOT (
    [VALUES] FOR [COL] IN (A1,A2,A3,A4,A5,A6)
) as unpvt
LEFT JOIN table2 t 
    ON t.KOD = unpvt.[COL]
ORDER BY ID_QUANTITY, [NO]

输出：

ID  ID_QUANTITY VALUES
1   500         4,1
2   500         4,2
3   500         1,5
4   500         3,7
5   500         3,9
6   600         3
7   600         0
8   600         0
9   600         2,1
10  600         2,6
...
25  900         2,4
26  1000        2,4
27  1000        34,2
28  1000        1,2
29  1000        21,2
30  1000        10,2

Answer 2

使用UNPIVOT

SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)),
    t2.ID_Quantity,
    t1.Value 
FROM Table2 t2
INNER JOIN 
(
            SELECT * 
            FROM Table1
            UNPIVOT 
            (
                [Values] FOR [Columns] IN ([A1], [A2],[A3], [A4], [A5],[A6])
            ) as pvt
) t1
ON t1.Columns = t2.KOD

Answer 3

尝试这个 ：

创建table3 （ ID_QUANTITY int（11）， VALUE int（11））;

for($i=1;$i<6;$i++){ $insert=mysql_query("insert into table3 select a.ID_QUANTITY,bA$i from table2 a,table1 b where a.KOD='A$i'); }