[英]JPA specification CriteriaBuilder for @ManyToOne
我正在尝试执行一些过滤,但是在ManyToOne进行过滤时遇到了一些问题,并且每次获得结果集时,无论它们通过哪个项目链接,我都会得到所有Task对象。 我有以下实体:
@Entity
public class Project implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "project_seq_gen")
@SequenceGenerator(name = "project_seq_gen", sequenceName = "project_id_seq", allocationSize = 1)
private Long id;
@Column(unique = true)
private String projectId;
//more things
}
和通过ID与项目链接的任务类
@Entity
public class Task implements Serializable {
@Id
private String id;
@Column
private String name;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "project_tasks")
private Project project;
@Column
private Enum<TaskType> type;
//more things....
}
在任务表中看起来像这样
|id |project_tasks |
|--------|--------------|
| TASK1 | 1 |
| TASK2 | 2 |
|--------|--------------|
我有jparepository可以搜索任务:
@Repository
public interface TaskRepository extends JpaRepository<Task, Integer> , JpaSpecificationExecutor {
以及使用由org.hibernate.jpamodelgen.JPAMetaModelEntityProcessor生成的元模型的Specification
public class TaskSpecification implements Specification<Task> {
private final TaskFilter taskFilter;
public TaskSpecification(TaskFilter task) {
this.taskFilter = task;
}
@Override
public Predicate toPredicate(Root<Task> task, CriteriaQuery<?> cq, CriteriaBuilder cb) {
Predicate predicate = cb.conjunction();
//project
//approach 1
cb.and(predicate, task.join(Task_.project).get(Project_.id).in(taskFilter.getProject().getId()));
//approach 2
cb.and(predicate, cb.equal(task.get(Task_.project).get(Project_.id), taskFilter.getProject().getId()));
//some other filters to follow
if (StringUtils.isNotBlank(taskFilter.getByState())) {
if (TaskFilter.OPEN.equals(taskFilter.getByState())) {
predicate = cb.and(predicate, task.get(Task_.state).in(TaskState.TO_DO, TaskState.ONGOING, TaskState.COMPLETE, TaskState.BLOCKED));
} else {
predicate = cb.and(predicate, task.get(Task_.state).in(TaskState.valueOf(taskFilter.getByState())));
}
}
return predicate;
}
}
服务电话:
public List<Task> findBySpecification(TaskFilter filter) {
return taskRepo.findAll(new TaskSpecification(filter));
}
不幸的是,无论使用方法1和方法2进行的每个查询都返回所有任务,无论项目ID是什么。 我还启用了hibernate.show_sql,控制台上显示了以下内容
方法1
Hibernate: select task0_.id as id1_12_, task0_.active as active2_12_, task0_.task_assignee as task_as21_12_, task0_.create_date as create_d3_12_, task0_.description as descript4_12_, task0_.due_date as due_date5_12_, task0_.estimate as estimate6_12_, task0_.estimated as estimate7_12_, task0_.finishDate as finishDa8_12_, task0_.inSprint as inSprint9_12_, task0_.lastUpdate as lastUpd10_12_, task0_.loggedWork as loggedW11_12_, task0_.name as name12_12_, task0_.task_owner as task_ow22_12_, task0_.parent as parent13_12_, task0_.priority as priorit14_12_, task0_.project_tasks as project23_12_, task0_.release_id as release24_12_, task0_.remaining as remaini15_12_, task0_.state as state16_12_, task0_.story_points as story_p17_12_, task0_.subtasks as subtask18_12_, task0_.task_order as task_or19_12_, task0_.type as type20_12_ from Task task0_ inner join Project project1_ on task0_.project_tasks=project1_.id where 1=1 and (task0_.state in (? , ? , ? , ?))
方法2
Hibernate: select task0_.id as id1_12_, task0_.active as active2_12_, task0_.task_assignee as task_as21_12_, task0_.create_date as create_d3_12_, task0_.description as descript4_12_, task0_.due_date as due_date5_12_, task0_.estimate as estimate6_12_, task0_.estimated as estimate7_12_, task0_.finishDate as finishDa8_12_, task0_.inSprint as inSprint9_12_, task0_.lastUpdate as lastUpd10_12_, task0_.loggedWork as loggedW11_12_, task0_.name as name12_12_, task0_.task_owner as task_ow22_12_, task0_.parent as parent13_12_, task0_.priority as priorit14_12_, task0_.project_tasks as project23_12_, task0_.release_id as release24_12_, task0_.remaining as remaini15_12_, task0_.state as state16_12_, task0_.story_points as story_p17_12_, task0_.subtasks as subtask18_12_, task0_.task_order as task_or19_12_, task0_.type as type20_12_ from Task task0_ where 1=1 and (task0_.state in (? , ? , ? , ?))
将会非常有用。 最好的祝福
您可能没有正确使用cb.and()函数。 此函数将返回一个新的组合谓词,而不是更改当前谓词。
所以代替
cb.and(predicate, task.join(Task_.project).get(Project_.id).in(taskFilter.getProject().getId()));
你应该有
predicate = cb.and(predicate, task.join(Task_.project).get(Project_.id).in(taskFilter.getProject().getId()));
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