HttpClient 中的授权承载令牌？

Question

我正在尝试使用 Java 中的 oauth2 授权令牌访问 API 这是客户端代码

DefaultHttpClient httpclient = new DefaultHttpClient(); 
HttpPost post = new HttpPost(http://res-api");
post.setHeader("Content-Type","application/json");
post.setHeader("Authorization", "Bearer " + finalToken);

JSONObject json = new JSONObject();
// json.put ...
// Send it as request body in the post request 

StringEntity params = new StringEntity(json.toString());
post.setEntity(params);

HttpResponse response = httpclient.execute(post);
httpclient.getConnectionManager().shutdown();

这将返回 401。

等效的 curl 命令使用相同的令牌没有问题：

curl -H "Content-Type:application/json" -H "Authorization:Bearer randomToken" -X POST -d @example.json http://rest-api

我尝试注销请求，看起来授权设置正确

DEBUG [2016-06-28 20:51:13,655] org.apache.http.headers: >> Authorization: Bearer authRandomToKen; Path=/; Domain=oauth2-server; Expires=Wed, 29 Jun 2016 20:51:13 UTC

我通过复制粘贴相同的标记来尝试 curl 命令，并且 t 工作正常

虽然我也看到了这条线

DEBUG [2016-06-28 20:51:13,658] org.apache.http.impl.client.DefaultHttpClient: Response contains no authentication challenges

Answer 1

我遇到过类似的情况，我能够通过以下方式做到这一点，我希望这会对其他人有所帮助。

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;

public class HttpURLConnectionExample {


    public static void main(String[] args) throws Exception {

        // Sending get request
        URL url = new URL("http://example-url");
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();

        conn.setRequestProperty("Authorization","Bearer "+" Actual bearer token issued by provider.");
        //e.g. bearer token= eyJhbGciOiXXXzUxMiJ9.eyJzdWIiOiPyc2hhcm1hQHBsdW1zbGljZS5jb206OjE6OjkwIiwiZXhwIjoxNTM3MzQyNTIxLCJpYXQiOjE1MzY3Mzc3MjF9.O33zP2l_0eDNfcqSQz29jUGJC-_THYsXllrmkFnk85dNRbAw66dyEKBP5dVcFUuNTA8zhA83kk3Y41_qZYx43T

        conn.setRequestProperty("Content-Type","application/json");
        conn.setRequestMethod("GET");


        BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
        String output;

        StringBuffer response = new StringBuffer();
        while ((output = in.readLine()) != null) {
            response.append(output);
        }

        in.close();
        // printing result from response
        System.out.println("Response:-" + response.toString());

    }
}

Answer 2

我试图使用 HttpClient 做类似的事情，我通过如下的小改动让它工作。

post.setHeader(HttpHeaders.CONTENT_TYPE,"application/json");
post.setHeader(HttpHeaders.AUTHORIZATION, "Bearer " + finalToken);

Answer 3

没有 401 错误我正在执行上面给出的代码来接收 Pipedream SSE 实时事件。下面的代码在 Eclipse 中工作正常。

包裹//////您的包裹名称在这里//////

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;

public class HttpURLConnectionExample {


public static void main(String[] args) throws Exception {

    // Sending get request
    URL url = new URL("https://your Server website");
    
    HttpURLConnection conn = (HttpURLConnection) url.openConnection();
    conn.setRequestProperty("Accept", "application/json");
    conn.setRequestProperty("Authorization","Bearer PLACE.HERE");
    
    //e.g. bearer token= eyJhbGciOiXXXzUxMiJ9.eyJzdWIiOiPyc2hhcm1hQHBsdW1zbGljZS5jb206OjE6OjkwIiwiZXhwIjoxNTM3MzQyNTIxLCJpYXQiOjE1MzY3Mzc3MjF9.O33zP2l_0eDNfcqSQz29jUGJC-_THYsXllrmkFnk85dNRbAw66dyEKBP5dVcFUuNTA8zhA83kk3Y41_qZYx43T

    //conn.setRequestProperty("Content-Type","application/json");
    
   conn.setRequestMethod("GET");
    
   
    
    BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
    String output;

    StringBuffer response = new StringBuffer();
   
    
    while ((output = in.readLine()) != null) {
        System.out.println("Response:-" + output.toString());
////you will get output in "output.toString()" ,Use it however you like
    }
    in.close();
    
}

}