如何使这个猜谜游戏起作用？

Question

我正在尝试制作一个猜谜游戏，在该游戏中，我提示用户输入一个秘密数字，而他有6次尝试将其正确设置。 我已经掌握了大部分内容，但是一旦他用尽了所有的努力我就无法告诉他“对不起，您用完了，机密数字是x”）

我的代码：

import java.util.*;
import java.util.Scanner;
public class GuessGame{
  static public void main(String[] args)
  {
    System.out.println("Welcome to the guessing game. I will pick a number between 1");
    System.out.println("and 100 and you will try to guess it in 6 tries or less. Here we go: ");

    for (int i = 6; i > 0; i--)
    {
      Random rand = new Random(); 
      int secNumber = rand.nextInt(5);
      int theNumber = secNumber;
      Scanner s = new Scanner(System.in);
      System.out.println("Enter a number: ");
      int guess = s.nextInt();

      if (guess == theNumber)
      {
        System.out.println("That's it! You guessed it, the number was: " +  theNumber + " and it took you " + (7 - i) + " tries.");
      }

      while(i > 0) {
      if (guess < theNumber)
      {
        System.out.println("The secret number is bigger than than that. You have " + (i - 1) + " tries left.");
        break;
      }
      else if (guess > theNumber)
      {
        System.out.println("The secret number is smaller than than that. You have " + (i - 1) + " tries left.");
        break;
      }

    }

为了告诉用户何时他有零次尝试然后透露秘密号，我尝试了一段时间（i == 0）{System.out.println（....）; 但是，它在第​​一个猜测之后立即生效。

Answer 1

while循环是不必要的，并且样式已关闭。 这是我的解决方法。

import java.util.*;
import java.util.Scanner;


public class GuessGame {
  public static void main(String[] args) {
    System.out.println("Welcome to the guessing game. I will pick a number between 1");
    System.out.println("and 100 and you will try to guess it in 6 tries or less. Here we go: ");
    int theNumber = rand.nextInt(5);
    for (int i = 6; i > 0; i--) {
      Random rand = new Random();
      Scanner s = new Scanner(System.in);
      System.out.println("Enter a number: ");
      int guess = s.nextInt();

      if (guess == theNumber) {
        System.out.println("That's it! You guessed it, the number was: " +  theNumber + " and it took you " + (7 - i) + " tries.");
      } else if (guess < theNumber) {
        System.out.println("The secret number is bigger than than that. You have " + (i - 1) + " tries left.");
      } else if (i == 1) {
        System.out.println("You could not guess the number");
      } else {
        System.out.println("The secret number is smaller than than that. You have " + (i - 1) + " tries left.");
      } 
    }
  }
}

Answer 2

1. while循环是不必要的。
2. 在for循环外分配secNumber 。
3. 变量theNumber是不必要的。
4. 您需要将rand.nextInt(5)替换为rand.nextInt(100) + 1 ，以使数字介于1和100之间（含1和100）。
5. 将i - 1更改为i因为猜测计数将等于i 。
6. 从if块中删除break ，因为这些会使您离开游戏。
7. 在第一个if语句中添加break （如果他们赢了）

8. 添加if语句，让玩家知道游戏已经结束。

    import java.util.*; import java.util.Scanner; public class GuessGame { public static void main(String[] args) { System.out.println("Welcome to the guessing game. I will pick a number between 1"); System.out.println("and 100 and you will try to guess it in 6 tries or less. Here we go: "); Random rand = new Random(); int secNumber = rand.nextInt(100) + 1; // 2 4 for (int i = 6; i > 0; i--) { Scanner s = new Scanner(System.in); System.out.println("Enter a number: "); int guess = s.nextInt(); if (guess == secNumber) { System.out.println("That's it! You guessed it, the number was: " + secNumber + " and it took you " + (7 - i) + " tries."); break; // 7 } else if (guess < theNumber) { System.out.println("The secret number is bigger than than that. You have " + i + " tries left."); // 5 } else if (guess > theNumber) { System.out.println("The secret number is smaller than than that. You have " + i + " tries left."); // 5 } if(i == 1) // 8 { System.out.println("Out of tries."); } } } }