如何减少Javascript中多个变量上的对象数组？

Question

我想知道如何基于几个属性来减少大量对象。 该数组如下所示：

[{count:4, district:19, to_timestamp:"2015-09-24T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"},
{count:6, district:12, to_timestamp:"2015-09-24T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"},
{count:14, district:19, to_timestamp:"2015-10-01T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"},
{count:4, district:19, to_timestamp:"2015-09-24T00:00:00.000Z", type:"VANDALISM"},
...
{count:4, district:19, to_timestamp:"2016-03-24T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"},
{count:7, district:10, to_timestamp:"2016-03-24T00:00:00.000Z", type:"ASSAULT"}]

结果减少的对象数组需要包括任何给定日期（ to_timestamp ）上给定犯罪type每个district的合计count ； 日期是每周。 就像是：

[{key: "MOTOR VEHICLE THEFT", value: 57, date:"2015/09/23"},
...
  {key: "ASSAULT", value: 77, date:"2016/03/23"}]

我已经在使用Moment进行日期转换了。

Answer 1

您可以将一个对象用作所需组的哈希表（ type和to_timestamp ），并使用Array#forEach迭代该数组。

 var data = [{ count: 4, district: 19, to_timestamp: "2015-09-24T00:00:00.000Z", type: "MOTOR VEHICLE THEFT" }, { count: 6, district: 12, to_timestamp: "2015-09-24T00:00:00.000Z", type: "MOTOR VEHICLE THEFT" }, { count: 14, district: 19, to_timestamp: "2015-10-01T00:00:00.000Z", type: "MOTOR VEHICLE THEFT" }, { count: 4, district: 19, to_timestamp: "2015-09-24T00:00:00.000Z", type: "VANDALISM" }, { count: 4, district: 19, to_timestamp: "2016-03-24T00:00:00.000Z", type: "MOTOR VEHICLE THEFT" }, { count: 7, district: 10, to_timestamp: "2016-03-24T00:00:00.000Z", type: "ASSAULT" }], groupBy = ['type', 'to_timestamp'], grouped = []; data.forEach(function (a) { var key = groupBy.map(function (k) { return a[k]; }).join('|'); if (!this[key]) { this[key] = { key: a.type, value: 0, date: a.to_timestamp.slice(0, 10).replace(/-/g, '/') }; grouped.push(this[key]); } this[key].value += a.count; }, Object.create(null)); console.log(grouped); 

Answer 2

但是我认为减少对象比数组更容易。 获得对象后，可以将其转换为数组

此代码只是将data和type到对象键中。 没有加district 。

 const object = [{count:4, district:19, to_timestamp:"2015-09-24T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"}, {count:6, district:12, to_timestamp:"2015-09-24T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"}, {count:14, district:19, to_timestamp:"2015-10-01T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"}, {count:4, district:19, to_timestamp:"2015-09-24T00:00:00.000Z", type:"VANDALISM"}, {count:4, district:19, to_timestamp:"2016-03-24T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"}, {count:7, district:10, to_timestamp:"2016-03-24T00:00:00.000Z", type:"ASSAULT"}] // reduce a object .reduce( ( res, item) => { const date = moment(item.to_timestamp).format('YYYY/MM/DD') const key = item.type + date if ( !res[key] ) { res[key] = {key: item.type, date: date, value: item.count} } else { res[key]['value'] += item.count } return res }, {} ) //get a object, and then the object to array //console.log(object) var result = [] for ( var key in object ) { result.push(object[key]) } console.log(result) 

 <script src="http://momentjs.com/downloads/moment.min.js"></script> 

Answer 3

我认为您可以使用一个简单的Array.prototype.forEach循环来做到这一点：

 var crimes = [ {count:4, district:19, to_timestamp:"2015-09-24T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"}, {count:6, district:12, to_timestamp:"2015-09-24T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"}, {count:14, district:19, to_timestamp:"2015-10-01T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"}, {count:4, district:19, to_timestamp:"2015-09-24T00:00:00.000Z", type:"VANDALISM"}, {count:4, district:19, to_timestamp:"2016-03-24T00:00:00.000Z", type:"MOTOR VEHICLE THEFT"}, {count:7, district:10, to_timestamp:"2016-03-24T00:00:00.000Z", type:"ASSAULT"} ]; var dict = {}, result = []; crimes.forEach(crime => { var date = new Date(crime.to_timestamp); date.setDate(date.getDate() - date.getDay()); var hash = crime.type + date.toDateString() if (!dict[hash]) { dict[hash] = { count: crime.count, key: crime.type, date: date }; result.push(dict[hash]) } else dict[hash].count += crime.count; }); console.log(result);