[英]sorting an array of objects
我有一个方法可以按名字对对象数组进行排序,可以很好地打印出来。 但是,当我要打印对象的原始顺序时,它仍然会打印出已排序的版本。 我可以更改以解决此问题吗?
主要方法+其他方法
String[] firstNames= {"Fred","John","Amir", "James","Bob","Jay","Amber"};
String[] lastNames = {"Bond","Kates","Memar", "White","Marley","Brown","Nogofski"};
String[] idNumbers = {"R111111","A222222","AB11111", "KR22121","V311133","L242434","P102432"};
String[] employeeNum = {"1111","2222","3333", "4444","5555","6666","7777"};
Employee[] list = new Employee[firstNames.length];
list = listOfEmployees(firstNames,lastNames,idNumbers); // create the list of employees in one array
System.out.println("List of employees before sorting...\n");
printEmployeeList(list); //print the list of employees
sortWithFirstName(list);
printEmployeeList(list);
public static void printEmployeeList(Employee[] list){
String employees = Arrays.toString(list).replace("[", "").replace("]", "").replace(",", "");
System.out.println(employees);
}
public static Employee[] sortWithFirstName(Employee[] list){
System.out.println("Sorting the list with the first name");
{
boolean swap;
//String temp; //change this too
do
{
swap = false;
for (int i = 0; i < (list.length - 1); i++)
{
if (list[i].getFirstName().compareTo(list[i+1].getFirstName()) > 0) //if first number is greater then second then swap
{
//swap
Employee temp = list[i];
list[i] = list[i + 1];
list[i + 1] = temp;
swap = true;
}
}
} while (swap == true);
printEmployeeList(list);
}
return list;
}
员工阶层
public static class Employee{
private String firstName;
private String lastName;
private String idNumber;
private String employeeNumber;
private int employeeCount;
/**
* Constructor
* @param firstName first name
* @param lastName last name
* @param idNumber id number
*/
public Employee(String firstName, String lastName, String idNumber){
this.firstName = firstName;
this.lastName = lastName;
this.idNumber = idNumber;
employeeCount = 0;
}
/**
* Accessors here
*/
public String getFirstName(){
return firstName;
}
public String getLastName(){
return lastName;
}
public String getIdNumber(){
return idNumber;
}
public String getEmployeeNumber(){
return employeeNumber;
}
// mutators here
/**
* @param firstName first name
*/
public void setFirstName(String firstName){
this.firstName = firstName;
}
/**
* @param lastName last name
*/
public void setLastName(String lastName){
this.lastName = lastName;
}
/**
* @param idNumber id number
*/
public void setIdNumber(String idNumber){
this.idNumber = idNumber;
}
/**
* @param employeeNumber employee number
*/
public void setEmployeeNumber(String employeeNumber){
this.employeeNumber = "";
}
@Override
public String toString(){
String result = "\nFirst name: " + getFirstName() + "\nLast name: " + getLastName()
+ "\nId number: " + getIdNumber() + "\nEmployee number: ";
if(getEmployeeNumber() == null){
return result + "No employee number has been assigned yet!\n";
}
return result + getEmployeeNumber() + "\n";
}
}
我认为当您对原始数组进行排序时,您需要创建一个新的数组实例,而不是直接在其中进行操作,而是使用新实例,因此当您返回原始数组时,您会发现它就像创建一个排序之前一样从原始数组复制
在这里,您将打印原始订单,然后重新排列列表变量。 如果再次打印该列表,因为它是相同的变量,它将被重新排列。
printEmployeeList(list); //print the list of employees
sortWithFirstName(list);
printEmployeeList(list);
您需要创建原始列表的副本,然后重新排列该副本(例如listArranged),然后,如果要打印原始列表,则可以访问第一个list
变量。
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