[英]Program crash accessing dynamically allocated array from function in C
感谢您抽时间阅读。 尝试访问以前在函数中动态分配的数组时,我程序崩溃。 这是一些代码
//function to allocate my array, gives an array as return
Player* allocate(Player **a, int n) {
*a = (Player *) malloc(sizeof(Player)*(n));
return *a;
}
//populating my allocated array, return an array
Player* initializePlayers(Player *a, int n){
int i=0;
char tmp[MAXCHAR];
for(i=0; i<n; i++){
printf("Insert player name %d\n", i);
scanf("%s", tmp);
strcpy(a[i].playerName,tmp);
printf("Player %s assigned.\n", a[i].playerName);
a[i].playerNumber=i;
}
return a;
}
//setup function which includes both the above ones, called from main
void setup(Player *array, int *nPlayers){
int done=0;
while (done==0){
printf("How many players?\n");
scanf("%d", nPlayers);
if (*nPlayers <2 || *nPlayers>8){
printf("Choose between 2 and 8\n");
waitFor(2);
clear();
done=0;
}
else done=1;
}
allocate(&array, *nPlayers);
initializePlayers(array, *nPlayers);
}
从我的main
Player * array=NULL;
//I'm passing nPlayers because i want the value to be saved and available on my main
setup(array, &nPlayers);
for (i=0; i<nPlayers; i++){
printf("It's %s 's turn\n", (array)[i].playerName);
dices=diceRoll(&same);
}
我是编程新手,所以我可能会缺少一些实际上很明显的东西,请不要认为任何事情都是理所当然的
在函数setup()
对复制的参数array
修改不会影响函数main()
局部变量。 取消引用NULL
将调用未定义的行为,并且您的程序刚巧崩溃 。
您的setup()
应该像这样:
void setup(Player **array, int *nPlayers){
/* ... */
allocate(array, *nPlayers);
initializePlayers(*array, *nPlayers);
}
它应该这样称呼:
Player * array=NULL;
//I'm passing nPlayers because i want the value to be saved and available on my main
setup(&array, &nPlayers);
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