[英]SQL Server - List of parameters into function, Export Multiple results into Excel
我有一个函数,将ID作为输入。 该功能从您输入的ID中获取所有相关ID。 当我使用不同的ID号运行该函数五次时,例如:
select * from [levelfunction](100)
select * from [levelfunction](101)
select * from [levelfunction](102)
select * from [levelfunction](104)
select * from [levelfunction](108)
CREATE TABLE #Table1(
ID [int] NULL,
Level [int] NULL)
INSERT INTO #Table1 (ID, Level) VALUES (100,0)
CREATE TABLE #Table2(
ID [int] NULL,
Level [int] NULL)
INSERT INTO #Table2 (ID, Level) VALUES (101,0)
CREATE TABLE #Table3(
ID [int] NULL,
Level [int] NULL)
INSERT INTO #Table3 (ID, Level) VALUES (102,0)
CREATE TABLE #Table4(
ID [int] NULL,
Level [int] NULL)
INSERT INTO #Table4 (ID, Level) VALUES (103,0), (104,1), (105,2), (106,3)
CREATE TABLE #Table5(
ID [int] NULL,
Level [int] NULL)
INSERT INTO #Table5 (ID, Level) VALUES (107,0), (108,1), (109,2)
我得到以下结果:
select * from #Table1
select * from #Table2
select * from #Table3
select * from #Table4
select * from #Table5
+-----+-------+
| ID | Level |
+-----+-------+
| 100 | 0 |
+-----+-------+
+-----+-------+
| ID | Level |
+-----+-------+
| 101 | 0 |
+-----+-------+
+-----+-------+
| ID | Level |
+-----+-------+
| 102 | 0 |
+-----+-------+
+-----+-------+
| ID | Level |
+-----+-------+
| 103 | 0 |
| 104 | 1 |
| 105 | 2 |
| 106 | 3 |
+-----+-------+
+-----+-------+
| ID | Level |
+-----+-------+
| 107 | 0 |
| 108 | 1 |
| 109 | 2 |
+-----+-------+
我如何 -
-在不更改功能的情况下将ID列表放入功能中?
-将所有表导出到excel作为1结果?
Expected excel result:
+-----+-------+
| ID | Level |
+-----+-------+
| 100 | 0 |
| 101 | 0 |
| 102 | 0 |
| 103 | 0 |
| 104 | 1 |
| 105 | 2 |
| 106 | 3 |
| 107 | 0 |
| 108 | 1 |
| 109 | 2 |
+-----+-------+
对于
在不更改功能的情况下将ID列表放入功能中?
使用交叉申请
declare @IDlist table(ID int)
insert into @IDlist(ID) values (100),(101),(102),(103),(104),(105),(106),(107)
select a.Id,a.Level from @IDlist d
cross apply levelfunction(d.ID) as a;
关于导出到excel的回答不止一次,例如,这里链接服务器“(null)”的OLE DB访问接口“ Microsoft.ACE.OLEDB.12.0”返回消息“书签无效”。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.