如何解决ado.net中的错误“多部分标识符”

Question

我有以下查询，它在SQL Server 2008中工作正常，但是当我在ADO.NET中连接时，它显示此错误：

无法绑定多部分标识符“ v.ClientId”。
无法绑定多部分标识符“ v.ClientId”。
无法绑定多部分标识符“ v.ClientID”。
多部分标识符“ v.Fare”无法绑定。
无法绑定多部分标识符“ v.ClientId”。

查询：

SELECT
    f.ID, f.ClientID, vc.Name, 
    f.Fare as FixFares, v.Fare as VehicleFare, 
    f.FromPostCode, f.ToPostCode, f.[From], f.[To],
    v.ClientId, v.IsActive, v.VehicleID, vc.ID
FROM
    VehicleFixeFare AS v
INNER JOIN 
    FixFare f ON v.ClientId = f.ClientId 
INNER JOIN
    Vehicle vc ON v.ClientId = vc.ClientId
WHERE
    v.ClientID = 159

下面的代码

conn = new SqlConnection(Connection1);
conn.Open();

//  var LIST=(from a in General.GetQueryable<Ve>)
string Query = "select f.ID, f.ClientID, vc.Name, f.Fare as FixFares, v.Fare as VehicleFare, f.FromPostCode, "+
               "f.ToPostCode, f.[From], f.[To], v.ClientId, v.IsActive, v.VehicleID, vc.ID " +  
               "from  VehicleFixeFare as v"+
               "inner join FixFare f on v.ClientId = f.ClientId inner join Vehicle vc on v.ClientId = vc.ClientId where v.ClientID =" + ClientID;

SqlDataAdapter ad = new SqlDataAdapter(Query, conn);
dt = new DataTable();

ad.Fill(dt);

Answer 1

我将像这样执行代码，它将消除空间问题，该问题很可能是导致错误的原因，并且可读性更好。

string Query = 
        @"select f.ID, f.ClientID, vc.Name, f.Fare as FixFares, v.Fare as VehicleFare, f.FromPostCode, 
                    f.ToPostCode, f.[From], f.[To], v.ClientId, v.IsActive, v.VehicleID, vc.ID 
            from  VehicleFixeFare as v
            inner join FixFare f on v.ClientId = f.ClientId 
            inner join Vehicle vc on v.ClientId = vc.ClientId where v.ClientID =" + ClientID;

Answer 2

这是由于空间问题。 在每行的开头和结尾留一些空间，您的问题将得到解决。

string Query = " select f.ID, f.ClientID, vc.Name, f.Fare as FixFares, v.Fare       as VehicleFare, f.FromPostCode, "+
           " f.ToPostCode, f.[From], f.[To], v.ClientId, v.IsActive, v.VehicleID, vc.ID " +  
           " from  VehicleFixeFare as v "+
           " inner join FixFare f on v.ClientId = f.ClientId inner join Vehicle vc on v.ClientId = vc.ClientId where v.ClientID =" + ClientID;