Xamarin Rest Web服务不会反序列化

Question

我想在get方法中使用rest。 我的代码如下；

public class RegisterPage : ContentPage
{
    Label label, l4, label2;
    public RegisterPage()
    {
        Button btn = new Button
        {
            Text = "register"
        };

        btn.Clicked += Btn_Clicked;
        label = new Label();
        l4 = new Label();
        label2 = new Label();



        Content = new StackLayout
        {
            Children = {
                btn,
                label,
                l4,
                label2
            }
        };
    }

    private async void Btn_Clicked(object sender, EventArgs e)
    {

        HttpClient client = new HttpClient();
        client.DefaultRequestHeaders.Add(Constants.API_KEY_HEADER_KEY, Constants.API_KEY);
        string URL = Constants.URL;

        var response = await client.GetAsync(URL);

        var content = await response.Content.ReadAsStringAsync();
        var result = JsonConvert.DeserializeObject<Models.Result>(content);


        label.Text = result.Success.ToString();


        l4.Text = result.Error.ToString();
        label2.Text = ((RegisteredDevice)result.Retval).Clientuuid + " - " + ((RegisteredDevice)result.Retval).Deviceuuid;
    }
}

网址运作良好。 而且我的内容值具有json字符串。 但是序列化不起作用。

var result = JsonConvert.DeserializeObject（content）; 此代码不会反序列化。

我的模特是

public class Result
{
    private object retval = null;
    private bool success = false;
    private Error error = null;


    internal Error Error
    {
        get { return error; }
        set { error = value; }
    }

    public bool Success
    {
        get { return success; }
        set { success = value; }
    }

    public object Retval
    {
        get { return retval; }
        set { retval = value; }
    }
}

杰森：

{  
   "result":{  
      "retail":{  
         "@xsi.type":"registeredDevice",
         "clientuuid":"28asgargb-acfe‌​-41dfgsdg51",
         "deviceuuid":123456
      },
      "success":true
   }
}

Answer 1

我认为问题来自：

private object retval = null;

因此，对我而言，在C＃中构造序列化对象的最佳方法是使用以下网站：

http://json2csharp.com/

这将告诉您json是否正确，他将为您生成所需的类，这里是json2csharp生成的类

public class Retail
{
    public string __invalid_name__@xsi.type { get; set; }
    public string clientuuid { get; set; }
    public int deviceuuid { get; set; }
}

public class Result
{
    public Retail retail { get; set; }
    public bool success { get; set; }
}

public class RootObject
{
    public Result result { get; set; }
}