带有php和javascript的google adwords

Question

我正在借助google adwords转换跟踪用户会话。
我正在用Javascript编写代码，并在php中传递值。
我的整个代码是正确的，但是当我查看页面源代码（ctrl + u）时，没有显示google coverage标签。
我不知道发生了什么，有人可以帮我解决这个问题吗？

我被困在项目之间，还附加了页面源的屏幕截图

     <!-- Google Code for Search-UAE-English-Skincare-mobiiwold Conversion Page -->

      <script type="text/javascript">
      var conversion_label;
          $(document).ready(function() {
              var link = $(location).attr("href");
              if(link.includes("campaign/skin-care/")) {
                  conversion_label = "VEa_CMe_rmUQ45-p2gM";
              } else if( link.includes("campaign/obesity/")) {
                   conversion_label = "-Xq-CJCtwGUQ45-p2gM";
              } else if(link.includes("campaign/al-wasl-branch/")) {
                   conversion_label =" KhRoCMX8tGUQ45-p2gM";
              } else if(link.includes("campaign/worried-about-hairloss/")) {
                  conversion_label = "T8nbCJSR7mUQ45-p2gM";
              } else if(link.includes("campaign/ar-hair-loss/")) {
                  conversion_label = "7MhmCMSqgWYQ45-p2gM";
              } else if(link.includes("campaign/ar-skin-care/")) {
                  conversion_label  = "ef7rCLapwGUQ45-p2gM";
              } else if(link.includes("campaign/ar-obesity/")) {
                  conversion_label  = "YPVwCJyJuWUQ45-p2gM";
              } else if(link.includes("campaign/ar-allergy/")) {
                  conversion_label  == "95cLCNuzv2UQ45-p2gM";
              } else if(link.includes("campaign/ar-al-wasl-branch/")) {
                  conversion_label  = "OKx6CJ2nyGUQ45-p2gM";
              } 
          });         

          /* <![CDATA[ */
          var google_conversion_id = 994725859;
          var google_conversion_language = "en";
          var google_conversion_format = "3";
          var google_conversion_color = "ffffff";
          var google_conversion_label =<?php echo $conversion_label; ?>;
          var google_remarketing_only = false;


          /* ]]> */
      </script>
      <script type="text/javascript" src="//www.googleadservices.com/pagead/conversion.js">
      </script>
      <noscript>
          <div style="display:inline;">
              <img height="1" width="1" style="border-style:none;" alt="" src="//www.googleadservices.com/pagead/conversion/994725859/?label=<?php echo $conversion_label; ?>;guid=ON&amp;script=0" />
          </div>
      </noscript>

Answer 1

您将JS变量conversion_label设置为正确的值，但随后读取了PHP变量$conversion_label 。 我不明白为什么这里需要PHP，只需将行更改为

var google_conversion_label = conversion_label;