[英]How to access the content of simple type XML element via XSLT/XPath after transforming it to JSON and back to XML?
[英]How to use XPath/XSLT fn:json-to-xml
我需要将JSON字符串转换为XML字符串。 标签确实包含属性。 从本主题的答案中,我开始使用XSLT。
存在一个函数fn:json-to-xml 。 我了解它应该将JSON转换为不带属性的XML(我使用XSLT格式化)。
如何使用此功能?
因为它是在XSLT中实现的,所以我会在.xsl文件中进行猜测,但是找不到任何示例。
提前谢谢了!
该功能在XSLT 3.0,XPath 3.1和XQuery 3.1中定义。
使用它的最简单方法可能是安装Saxon-HE 9.7.0.7,然后从XQuery在命令行上运行它,如下所示:
java -cp /dddd/9.7.0.7/he/saxon9he.jar net.sf.saxon.Query -t -qs:"json-to-xml(unparsed-text('/eeee/test.json'))" -o:output.xml
这是一个简单的示例,摘自XSLT 3.0规范https://www.w3.org/TR/xslt-30/#func-json-to-xml ,示例输入可以是JSON格式的任何字符串,在下面使用包含带有JSON data
元素的XML文档:
<root>
<data>{
"desc" : "Distances between several cities, in kilometers.",
"updated" : "2014-02-04T18:50:45",
"uptodate": true,
"author" : null,
"cities" : {
"Brussels": [
{"to": "London", "distance": 322},
{"to": "Paris", "distance": 265},
{"to": "Amsterdam", "distance": 173}
],
"London": [
{"to": "Brussels", "distance": 322},
{"to": "Paris", "distance": 344},
{"to": "Amsterdam", "distance": 358}
],
"Paris": [
{"to": "Brussels", "distance": 265},
{"to": "London", "distance": 344},
{"to": "Amsterdam", "distance": 431}
],
"Amsterdam": [
{"to": "Brussels", "distance": 173},
{"to": "London", "distance": 358},
{"to": "Paris", "distance": 431}
]
}
}</data>
</root>
data
元素的模板然后简单地调用json-to-xml(.)
并调用整个样式表以演示结果输出返回的XML:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:math="http://www.w3.org/2005/xpath-functions/math"
exclude-result-prefixes="xs math"
version="3.0">
<xsl:output indent="yes"/>
<xsl:template match="data">
<xsl:copy-of select="json-to-xml(.)"/>
</xsl:template>
</xsl:stylesheet>
Saxon 9.7 HE的输出为
<map xmlns="http://www.w3.org/2005/xpath-functions">
<string key="desc">Distances between several cities, in kilometers.</string>
<string key="updated">2014-02-04T18:50:45</string>
<boolean key="uptodate">true</boolean>
<null key="author"/>
<map key="cities">
<array key="Brussels">
<map>
<string key="to">London</string>
<number key="distance">322</number>
</map>
<map>
<string key="to">Paris</string>
<number key="distance">265</number>
</map>
<map>
<string key="to">Amsterdam</string>
<number key="distance">173</number>
</map>
</array>
<array key="London">
<map>
<string key="to">Brussels</string>
<number key="distance">322</number>
</map>
<map>
<string key="to">Paris</string>
<number key="distance">344</number>
</map>
<map>
<string key="to">Amsterdam</string>
<number key="distance">358</number>
</map>
</array>
<array key="Paris">
<map>
<string key="to">Brussels</string>
<number key="distance">265</number>
</map>
<map>
<string key="to">London</string>
<number key="distance">344</number>
</map>
<map>
<string key="to">Amsterdam</string>
<number key="distance">431</number>
</map>
</array>
<array key="Amsterdam">
<map>
<string key="to">Brussels</string>
<number key="distance">173</number>
</map>
<map>
<string key="to">London</string>
<number key="distance">358</number>
</map>
<map>
<string key="to">Paris</string>
<number key="distance">431</number>
</map>
</array>
</map>
</map>
因此,与将输入作为as xs:string
任何其他函数一样as xs:string
您当然可以传递XSLT或XPath代码中具有的任何字符串值,也可以传递一个节点,然后将该节点首先原子化为字符串。
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