![](/img/trans.png)
[英]How to for each new object push it into array, with avoiding override? JavaScript
[英]How to push new property into each existing object within object array?
我正在尝试从多维数组中检索单个结果,然后将其推入对象数组中包含的每个对象中。
这是我的代码;
var data = { "questions": ["Q1", "Q2", "Q3"], "details": [{ "name": "Alex", "values": [27, 2, 14] }, { "name": "Bill", "values": [40, 94, 18] }, { "name": "Gary", "values": [64, 32, 45] }] } var question = "Q1"; var singleResult = []; for (var i = 0; i < data.details.length; i++) { var qIndex = data.questions.indexOf(question) singleResult.push(data.details[i].values[qIndex]) } for (var i = 0; i < singleResult.length; i++) { data.details.push({ single: singleResult[i] }) } console.log(data.details)
如您所见,它正在将一个新对象推入数组,而我希望将单个结果推入现有的3个对象。
所以我的新数组应该看起来像;
[{
"name": "Alex",
"values": [27, 2, 14],
"single": 27
}, {
"name": "Bill",
"values": [40, 94, 18],
"single": 40
}, {
"name": "Gary",
"values": [64, 32, 45],
"single": 64
}]
我以为使用.concat
运行循环可以.concat
,但遗憾的是事实并非如此(至少对我而言!)。
希望一切顺利,在此先感谢您的帮助/提前!
我会像这样重构它:
var data = { "questions": ["Q1", "Q2", "Q3"], "details": [{ "name": "Alex", "values": [27, 2, 14] }, { "name": "Bill", "values": [40, 94, 18] }, { "name": "Gary", "values": [64, 32, 45] }] } var question = "Q1"; var qIndex = data.questions.indexOf(question) data.details.forEach((obj) => { obj.single = obj.values[qIndex]; }); console.log(data.details)
强调:
您可以使用indexOf()
获取问题的索引,然后使用map()
获取修改后的数组。
var data = {"questions":["Q1","Q2","Q3"],"details":[{"name":"Alex","values":[27,2,14]},{"name":"Bill","values":[40,94,18]},{"name":"Gary","values":[64,32,45]}]} var question = "Q1"; var qIndex = data.questions.indexOf(question); var result = data.details.map(function(e) { var o = JSON.parse(JSON.stringify(e)); o.single = e.values[qIndex]; return o; }); console.log(result);
var data = { "questions": ["Q1", "Q2", "Q3"], "details": [{ "name": "Alex", "values": [27, 2, 14] }, { "name": "Bill", "values": [40, 94, 18] }, { "name": "Gary", "values": [64, 32, 45] }] } var question = "Q1"; var singleResult = []; for (var i = 0; i < data.details.length; i++) { var qIndex = data.questions.indexOf(question) singleResult.push(data.details[i].values[qIndex]) } for (var i = 0; i < singleResult.length; i++) { data.details[i].single = singleResult[i]; } console.log(data.details)
var data = {"questions": ["Q1", "Q2", "Q3"],"details": [{"name": "Alex","values": [27, 2, 14]}, {"name": "Bill","values": [40, 94, 18]}, {"name": "Gary","values": [64, 32, 45]}]}, question = "Q1", qIndex = data.questions.indexOf(question); for (var i = 0, len = data.details.length; i < len; i++) { data.details[i].single = data.details[i].values[qIndex]; } console.log(data.details);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.