不同嵌入式中的相同字段

Question

我有3个表A，B，C：

@Embeddable
public class AModel {
    @Column(name = "a_id", insertable = false, updatable = false)
    private int id;
    @Column(name = "a_name")
    private String name;
}

@Embeddable
public class BModel {
    @Column(name = "b_id", insertable = false, updatable = false)
    private int id;
    private int aId;
    @Column(name = "b_name")
    private String name;
}

@Embeddable
public class CModel {
    @Column(name = "c_id", insertable = false, updatable = false)
    private int id;
    private int aId;
    @Column(name = "c_name")
    private String name;
}

我有一个不变的实体

@Entity
@Immutable
public class AEntity {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "a_id")
    private int id;

    @Embedded
    private AModel aModel;
    @Embedded
    private BModel bModel;
    @Embedded
    private CModel cModel;
}

我使用EntityManager.createNativeQuery和以下查询创建的代码：

select * from A natural join B natural join C;

但我有一个例外，原因是：

org.hibernate.DuplicateMappingException:  Table [aentity] contains physical column name [a_id] represented by different logical column names: [a_id], [aId]

更新： 解决方案

向bModel和cModel添加以下注释可以解决此问题：

@AttributeOverrides({
            @AttributeOverride(name = "aId", column = @Column(name = "a_id", insertable = false, updatable = false))
    })

Answer 1

您正在将@ Id，@ Column与可嵌入的类AModel一起使用。 如果要将AModel用作复合键，则可以使用@EmbeddedId。 当您在AEntity中定义@Column（name = a_id）以及在可嵌入类AModel中定义相同的对象时，问题就来了，因此获取重复的逻辑映射。