数据透视表上的MySQL平均列

Question

我有一张桌子，像这样

loanprocessorusername     borrower     fundingdate
jonsmith                  borrower2    8/10/15
jonsmith                  borrower2    8/10/16
username3                 borrower4    9/9/15

等等等等。 基本上，我的任务是创建一个数据透视表，以获取给定年份中按月借贷用户名完成的借贷计数。 我实际上是在可以是任何领域时使用借款人来计数。 PK是贷款号

无论如何，这就是我走了多远：

SELECT loanprocessorusername, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 8 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2015 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Aug2015, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 9 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2015 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Sep2015, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 10 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2015 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Oct2015, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 11 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2015 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Nov2015, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 12 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2015 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Dec2015, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 1 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2016 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Jan2016, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2016 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Feb2016, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 3 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2016 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Mar2106, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 4 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2016 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Apr2016, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 5 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2016 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS May2016, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 6 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2016 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Jun2016, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 7 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2016 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Jul2016, 
   Count(CASE 
           WHEN Month(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 8 
                AND Year(Str_to_date(status_fundingdate, '%m/%d/%Y')) = 2016 
         THEN 
           borrower 
           ELSE NULL 
         END)      AS Aug2016, 
   Count(borrower) AS GrandTotal 
FROM   dataset 
WHERE  loan_lienposition = 'first' 
GROUP  BY loanprocessorusername; 

我想为平均添加最后一列，但是当我尝试执行avg（借款人）时，我得到的都是零。 如果我尝试做count（borrower）/ 13，这是月数，它没有给我想要的结果。 理想情况下，零应该为空，并且应该根据实际值的数量（非空）计算平均值。基本上我的问题是。 如何添加平均列以执行此数据透视表

谢谢

Answer 1

SELECT loanprocessorusername, 
       CONCAT(
               Month(Str_to_date(status_fundingdate, '%m/%d/%Y'),
               Year(Str_to_date(status_fundingdate, '%m/%d/%Y')
             ) AS MY,
       COUNT(1) AS COunt_Of_Loans_per_each_user
  FROM table 
GROUP BY 1,2
;